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![](https://rs.olm.vn/images/avt/0.png?1311)
\(a)\) \(\left|x-3\right|+4=\left|-6\right|\)
\(\Leftrightarrow \left|x-3\right|+4=6\)
\(\Leftrightarrow\left|x-3\right|=6-4\)
\(\Leftrightarrow\left|x-3\right|=2\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=2\\x-3=-2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=5\\x=1\end{cases}}\)
Vậy \(x=1\)
\(b)\) \(7-2\cdot\left|x+1\right|=\left(-3\right)^3\)
\(\Leftrightarrow7-2\cdot\left|x+1\right|=-27\)
\(\Leftrightarrow2\cdot\left|x+1\right|=7-\left(-27\right)\)
\(\Leftrightarrow2\cdot\left|x+1\right|=34\)
\(\Leftrightarrow\left|x+1\right|=34\div2\)
\(\Leftrightarrow\left|x+1\right|=17\)
\(\Leftrightarrow\orbr{\begin{cases}x+1=17\\x+1=-17\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=16\\x=-18\end{cases}}\)
Vậy \(x\in\left\{16;-18\right\}\)
Tìm x :
a, |x-3| + 4 = |-6|
<=> |x-3| + 4 = 6
<=> |x-3| = 6 - 4
<=> |x-3| = 2
<=> x - 3 = 2 hoặc x - 3 = -2
<=> x = 2 + 3 hoặc x = ( -2 ) + 3
<=> x = 5 hoặc x = 1
Vậy x € { 5 ; 1 }
b, 7 - 2 . |x+1| = ( - 3 )^3
<=> 7 - 2 . |x+1| = -27
<=> 2 . |x+1| = 7 + 27
<=> 2 . |x+1| = 34
<=> |x+1| = 34 : 2
<=> |x+1| = 17
<=> x + 1 = 17 hoặc x + 1 = -17
<=> x = 17 - 1 hoặc x = ( -17 ) - 1
<=> x = 16 hoặc x = -18
Vậy x € { 16 ; -18 }
![](https://rs.olm.vn/images/avt/0.png?1311)
5 - ( 2x - 7 ) = 3 . ( -4) + 20
5 - ( 2x - 7 ) = ( -12 ) + 20
5- ( 2x - 7 ) = 8
2x - 7 = 5 - 8
2x - 7 = -3
2x = -3 + 7
2x = 4
x = 4 : 2
x = 2
chúc bn hok tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
1a)1+2+3+...+x=0
\(\frac{x.\left(x+1\right)}{2}\)=0
x.(x+1) =0:2
x.(x+1) =0
x.(x+1) =0.1
vây x=0
tich dung cho minh nha
![](https://rs.olm.vn/images/avt/0.png?1311)
a) pt <=> \(\frac{x\left(x+1\right)}{2}=500500\)
<=> \(x^2+x=1001000\)
<=> \(x^2-1000x+1001x-1001000=0\)
<=> \(\left(x-1000\right)\left(x+1001\right)=0\)
<=> \(\orbr{\begin{cases}x=1000\\x=-1001\end{cases}}\)
Do \(x>0\)=> \(x=1000\)
b)
<=> \(2x=210\)
<=> \(x=105\)
c)
<=> \(6x-81=3.7\)
<=> \(x=17\)
d)
<=> \(125-5\left(3x-1\right)=5^2\)
<=> \(5\left(3x-1\right)=100\)
<=> \(3x-1=20\)
<=> \(x=7\)
e)
<=> \(4^{x+1}+1=65\)
<=> \(4^{x+1}=64\)
<=> \(x+1=3\)
<=> \(x=2\)
j)
<=> \(2\left(2x-3\right)=14\)
<=> \(2x-3=7\)
<=> \(x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(5.\left(x-3\right)=15\)
\(x-3=15:5\)
\(x-3=3\)
\(x=6\)
b)\(10+2.x=4^5:4^3\)
\(10+2.x=16\)
\(2x=16-10\)
\(2x=6\)
\(x=3\)
c) \(5^{x+1}=125\)
\(5^{x+1}=5^3\)
\(x+1=3\)
\(x=2\)
d) \(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}=2.5^2+5^2.3\)
\(5^{2x-3}=125\)
\(5^{2x-3}=5^2\)
\(2x-3=2\)
\(2x=6\)
\(x=3\)
Mk nhanh nek bn