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a) \(-x+821+534=499+\left(x-84\right)\)
\(-x-x=499-84-821-534\)
\(-2x=-940\)
\(x=470\)
b) \(x-96=\left(448-x\right)-150\)
\(x+x=448-150+96\)
\(2x=394\)
\(x=197\)
c) \(-\left(754+x\right)=\left(x-12-741\right)-23\)
\(-754-x=x-12-741-23\)
\(-x+x=-12-741-23+754\)
\(0x=2\)
\(x\)ko tồn tại
d) \(\left(6+x\right)-\left(17-21\right)=-25\)
\(6+x-17+21=-25\)
\(x=-25-6+17-21\)
\(x=-35\)
e) \(17-\left(x+2\right)=3\)
\(17-x-2=3\)
\(-x=3-17+2\)
\(-x=-12\)
\(x=12\)
h) \(-10-\left(31-x\right)=40\)
\(-10-31+x=40\)
\(x=40+10+31\)
\(x=81\)
k mk nha bạn
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a. Ta có: $1953=3^2.7.31$
$777=3.7.37$
$\Rightarrow UCLN(1953, 777) = 3.7=21$
b. Đề khó hiểu quá. Bạn xem lại/
Bài 2: Thiếu dấu giữa các số. Bạn xem lại.
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 4:
a: xy=-2
=>\(x\cdot y=1\cdot\left(-2\right)=\left(-2\right)\cdot1=\left(-1\right)\cdot2=2\cdot\left(-1\right)\)
=>\(\left(x,y\right)\in\left\{\left(1;-2\right);\left(-2;1\right);\left(-1;2\right);\left(2;-1\right)\right\}\)
b: \(\left(x-1\right)\left(y+2\right)=-3\)
=>\(\left(x-1\right)\cdot\left(y+2\right)=1\cdot\left(-3\right)=\left(-3\right)\cdot1=-1\cdot3=3\cdot\left(-1\right)\)
=>\(\left(x-1;y+2\right)\in\left\{\left(1;-3\right);\left(-3;1\right);\left(-1;3\right);\left(3;-1\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(2;-5\right);\left(-2;-1\right);\left(0;1\right);\left(4;-3\right)\right\}\)
Bài 3:
a: \(x\left(x+9\right)=0\)
=>\(\left[{}\begin{matrix}x=0\\x+9=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=0\\x=-9\end{matrix}\right.\)
b: \(\left(x-5\right)^2=9\)
=>\(\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=3+5=8\\x=-3+5=2\end{matrix}\right.\)
c: \(\left(7-x\right)^2=-64\)
mà \(\left(7-x\right)^2>=0\forall x\)
nên \(x\in\varnothing\)
Bài 2:
a: \(\left(-31\right)\cdot x=-93\)
=>\(31\cdot x=93\)
=>\(x=\dfrac{93}{31}=3\)
b: \(\left(-4\right)\cdot x=-20\)
=>\(4\cdot x=20\)
=>\(x=\dfrac{20}{4}=5\)
c: \(5x+1=-4\)
=>\(5x=-4-1=-5\)
=>\(x=-\dfrac{5}{5}=-1\)
d: \(-12x+1=-4\)
=>\(-12x=-4-1=-5\)
=>\(12x=5\)
=>\(x=\dfrac{5}{12}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
17x + 3. ( -16x – 37) = 2x + 43 - 4x
<=>17x-48x-111=-2x+43
<=>-29x=154
<=> \(x=-\frac{154}{29}\)
-3. (2x + 5) -16 < -4. (3 – 2x)
\(\Leftrightarrow-6x-31< -12+8x.\)
\(\Leftrightarrow-14x< 19\Rightarrow x< -\frac{19}{14}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ( x + 216 ) : 61 + 1 = 202
( x + 216 ) : 61 = 201
( x + 216 ) = 12261
x = 12045
b) 1818 : ( 6x - 37 ) + 1 = 19
1818 : ( 6x - 37 ) = 18
( 6x - 37 ) = 101
6x = 138
x = 23
c) ( x : 23 + 45 ) x 67 + 3 = 8914
( x : 23 + 45 ) x 67 = 8911
x : 23 + 45 = 133
x : 23 = 88
x = 2024
(x + 216) : 61 + 1 = 202
=> (x + 216) : 61 = 201
=> x + 216 = 12261
=> x = 12045
vậy_
1818 : (6x - 37) + 1 = 19
=> 1818 : (6x - 37) = 18
=> 6x - 37 = 101
=> 6x = 138
=> x = 23
vậy_
(x : 23 + 45) x 67 + 3 = 8914
=> (x : 23 + 45) x 67 = 8911
=> x : 23 + 45 = 133
=>x : 23 = 88
=> x = 2024
vậy_
![](https://rs.olm.vn/images/avt/0.png?1311)
1
a, -114
b, -1000
c, 87
d, 164
e, 981
2
a, x=14
b, x E {-32,2}
c, đề sai
d, 262
e, -3
g, đề sai
h, -3
40:[2.(x-19)]=5
2(x-19)=8
x-19=4
x=23
34-3(x+1)^3=37
3(x+1)^3=(-3)
(x+1)^3=(-1)
x+1=(-1)
x=(-2)
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