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\(\Leftrightarrow4x-8+7⋮x-2\)
\(\Leftrightarrow x-2\in\left\{1;-1;7;-7\right\}\)
hay \(x\in\left\{3;1;9;-5\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,0.25x\) - \(\frac{2}{3}x\) =\(1\frac{1}{6}\)
\(\Rightarrow x\cdot\left(0.25-\frac{2}{3}\right)=1\frac{1}{6}\)
\(\Rightarrow x\cdot\frac{-5}{12}=\frac{7}{6}\)
\(\Rightarrow x=\frac{7}{6}:\frac{-5}{12}\)
\(\Rightarrow x=\frac{-14}{5}=-2.8\)
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a)2+4+6+..+2x=210
=>2*1+2*2+...+2*x=210
=>2(1+2+3+...+x)=210
=>2[x(x+1)/2]=210
=>x*(x+1)=210
hay x*(x+1)=14(14+1)
vậy x=14
c)x+(x+1)+(x+2)+...+(x+2010)
=>(x+x+x+...+x)+(1+2+3+...+2010)=2029099
=>2011x + 2021055 =2029099
2011x =2029099-2021055
2011x =8044
x =8044 /2011
x =4
k cho mình nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\dfrac{3}{8}=\dfrac{6}{x}\\ \Rightarrow x=6:\dfrac{3}{8}\\ \Rightarrow x=16\\ b,\dfrac{1}{9}=\dfrac{x}{27}\\ \Rightarrow x=\dfrac{1}{9}.27\\ \Rightarrow x=3\\ c,\dfrac{4}{x}=\dfrac{8}{6}\\ \Rightarrow x=4:\dfrac{4}{3}\\ \Rightarrow x=3\\ d,\dfrac{3}{x-5}=\dfrac{-4}{x+2}\\ \Rightarrow3\left(x+2\right)=-4\left(x-5\right)\\ \Rightarrow3x+6=-4x+20\\ \Rightarrow3x+6+4x-20=0\\ \Rightarrow7x-14=0\\ \Rightarrow7x=14\\ \Rightarrow x=2\)
a: =>6/x=3/8
hay x=16
b: =>x/27=1/9
nên x=3
c: =>4/x=4/3
nên x=3
d: =>3/x-5=-4/x+2
=>3x+2=-4x+20
=>7x=18
hay x=18/7
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\)
\(\Rightarrow\frac{3}{2}x-\frac{1}{3}x=-\frac{1}{4}+\frac{2}{5}\)
\(\frac{7}{6}x=\frac{3}{20}\Rightarrow x=\frac{9}{70}\)
b) \(-5^{\frac{1}{2}x+1}=\frac{3}{4}-\frac{7}{6}\)
\(-5^{\frac{1}{2}x}.\left(-5\right)=-\frac{5}{12}\)
\(-5^{\frac{1}{2}x}=\frac{1}{12}\)
mà -51/2x mang giá trị âm
1/12 có giá trị dương
=> không tìm được x
c) \(\frac{2x-2}{3}=\frac{7x+3}{2-1}\)
\(\frac{2x-2}{3}=7x+3=\frac{21x+9}{3}\)
=> 2x - 2 = 21x + 9
=> 2x - 21x = 9 + 2
-19x = 11
x = -11/19
phần d bn lm như phần a nha
![](https://rs.olm.vn/images/avt/0.png?1311)
x.(x+1)=1563750
x.x+x=1563750
x^2+x=1250^2+1250
=>x=1250
ai thấy mk đúng thì ****!!!!!!
3x(x-1)-2(x+2)=4(1-x)-6
3x2-3x-2x-4=4-4x-6
3x2-3x-2x+4x=4-6+4
3x2-x=2
3x2-x-2=0
3x2+x-2x-2=0
3x(x+1)-2(x+1)=0
(x+1)(3x-2)=0
x+1=0 hoặc 3x-2=0
x=1 hoặc x=2/3