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bạn nguễn đăng khôi có thể làm có cả biểu thức a,b,c được ko
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c) x+x-1+x-2+x-3+...+x-50=255
51x-(50+49+48+...+1)=255
51x-1275=255
51x=255+1275
51x=1530
x=1530:51
x=30
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
\(\frac{1}{x}+\frac{2}{x}+\frac{3}{x}+\frac{4}{x}+...+\frac{50}{x}=255\)
\(\Rightarrow\frac{1+2+3+....+50}{x}=255\)
\(\Rightarrow\frac{\frac{50.51}{2}}{x}=255\)
\(\Rightarrow\frac{1275}{x}=255\Leftrightarrow x=\frac{1275}{255}=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
x+(x-1)+(x-2)+...+(x-50)=255
x+(x+x+x+.....+x)-(1+2+3+...+50)=255
x+50x-1275=255
51x-1275
51x=1275+255
51x=1530
x=1530/51
x=30
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x+0,9=20,17\Leftrightarrow x=20,17-0,9=19,24\)
\(47,5-x=4,64\Leftrightarrow x=47,5-4,64=42,86\)
\(3x=\dfrac{5}{4}-\dfrac{1}{2}\Leftrightarrow3x=\dfrac{3}{4}\Leftrightarrow x=\dfrac{1}{4}\)
\(a.x=20,17-0,9=19,27\)
\(b.47,5-x=4,56\Leftrightarrow x=42,86\)
\(c.3.x=\dfrac{5}{4}-\dfrac{1}{2}\Leftrightarrow3x=\dfrac{3}{4}\Leftrightarrow x=\dfrac{1}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x+(x+1)+(x+2)+…+(x+30)=1240
=>x+x+1+x+2+x+3+…+x+30=1240
=>x+x+x+…+x+1+2+3+…+30=1240
Từ 1->30 có: (30-1):1+1=30(số)
=>31.x+(30+1).30:2=1240
=>31.x+31.15=1240
=>31.x+465=1240
=>31.x=1240-465
=>31x=775
=>x=775:31
=>x=25
51x - [1+2+3+...+50] =255
=> 51x - 50 x 51 : 2 = 255
=> 51x - 1275 =255
=> 51x = 1530
=> x = 30
\(51x-\left(1+2+3+..+50\right)=255\)
\(51x-\frac{51.50}{2}=255\)
\(51x-1275=255\)
\(\Rightarrow51x=255+1275\)
\(\Rightarrow51x=1530\)
\(\Rightarrow x=30\)