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\(\frac{1}{x}=\frac{2}{y}\Rightarrow\frac{x}{1}=\frac{y}{2}=\frac{x+y}{1+2}=\frac{4}{3}\)
=> x=4/3.1=4/3
y=4/3.2=8/3
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\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+1}\cdot\left(x-7\right)^{10}=0\)
\(\left(x-7\right)^{x+1}\cdot\left[1-\left(x-7\right)^{10}\right]=0\)
\(\Rightarrow\hept{\begin{cases}\left(x-7\right)^{x+1}=0\\1-\left(x-7\right)^{10}=0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=7\\\left(x-7\right)^{10}=1\end{cases}}\)
Bạn xét nốt TH \(\left(x-7\right)^{10}=1\)nhé
\(\Rightarrow\hept{\begin{cases}x=7\\\hept{\begin{cases}x-7=1\\x-7=-1\end{cases}}\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=7\\\hept{\begin{cases}x=7\\x=6\end{cases}}\end{cases}}\)
( x - 7 )x + 1 - ( x - 7 )x + 11 = 0
=> ( x - 7 )x + 1 .[ 1 - ( x - 7 )10] = 0
=>( x - 7 )x + 1 = 0 hoặc 1 - ( x - 7 )10 = 0
x - 7 = 0 hoặc ( x - 7 )10 = 0
x - 7 = 0 hoặc / x - 7 / = 1
x - 7 = 0 hoặc x - 7 = 1 hoặc x - 7 = -1
=> x = 7 hoặc x = 8 hoặc x = 6
Hok tốt !
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a)\(x=-\frac{4}{7}\Rightarrow\left|x\right|=\left|-\frac{4}{7}\right|=\frac{4}{7}\)
b)\(x=\frac{-3}{-11}=\frac{3}{11}\Rightarrow\left|x\right|=\left|\frac{3}{11}\right|=\frac{3}{11}\)
c)\(x=-0,749\Rightarrow\left|x\right|=\left|-0,749\right|=0,749\)
d)\(x=-34\Rightarrow\left|x\right|=\left|-34\right|=34\)
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\(\Leftrightarrow\left(x-7\right)^{x+1}\left[1-\left(x-7\right)^{10}\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-7\right)^{x+1}=0\\\left(x-7\right)^{10}=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-7=0\\x-7=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=8\end{matrix}\right.\)
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<=> (x-7)^x+11 - (x-7)^x+1 = 0 ( chuyển vế cho thành đẳng thức rồi chuyển lại) <=> (x-7)^x+1 [(x-7)^x+10 -1 ] = 0 <=> \(\orbr{\begin{cases}\left(x-7\right)^{x+1}=0\\\left[\left(x-7\right)^{x+10}-1\right]=0\end{cases}\Rightarrow\orbr{\orbr{\orbr{\begin{cases}x-7=0\\\left(x-7\right)^{x+10}=1\end{cases}}}}}\) => x=7
xét x+10 lẻ => x-7=1 => x=8
tương tự với x+10 chẳn
![](https://rs.olm.vn/images/avt/0.png?1311)
( x - 7 )x+1 - ( x - 7 )x+11 = 0
( x - 7 )x+1 . [ 1 - ( x - 7 )10 ] = 0
\(\Leftrightarrow\orbr{\begin{cases}x-7=0\\\left(x-7\right)^{10}=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=7\\x-7=1\text{ hoặc }-1\end{cases}}\)
\(\Leftrightarrow x\in\left\{6,7,8\right\}\)
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\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
=> (x-7)x . (x-7) - (x-7)x . (x-7)11 = 0
=> \(\left(x-7\right)^x.\left[\left(x-7\right)-\left(x-7\right)^{11}\right]=0\)
=> [(x-7) - (x-7)11 ] = 0
=> \(\left\{\left(x-7\right).\left[1-\left(x-7\right)^{10}\right]\right\}=0\)
\(\Rightarrow\orbr{\begin{cases}x-7=0\\1-\left(x-7\right)^{10}=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=7\\\left(x-7\right)^{10}=1\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=7\\\left(x-7\right)^{10}=\left(-1\right)^{10}=1^{10}\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x=7\\x-7=1\\x-7=-1\end{cases}}\Rightarrow\hept{\begin{cases}x=7\\x=8\\x=6\end{cases}}\)
Vậy x thuộc { 6,7,8}
cố đúng k vậy bạn được bn phần trăn ạ