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Bài làm
a, x - 3 = -6 b, x-(-5) = 4 c, x - ( -9 ) = 4 - ( -9 ) d, 4 - x = -3 - ( -6 )
x = -6 + 3 x + 5 = 4 x + 9 = 4 + 9 4 - x = 3
x = -3 x = 4 - 5 x + 9 = 13 x = 4 - 3
Vậy x = -3 x = 9 x = 13 - 9 x = 1
Vậy x = 9 x = 4 Vậy x = 1 Vậy x = 4
# Chúc bạn học tốt #
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541+(218-x)=375
541+218-x=375
759-x=375
x=384
5 .(x+35)=515
x+35=103
x=68
10+2.x=4^5:4
10+2.x=256
2x=246
x=123
96-3.(x+1)=42
3(x+1)=54
x+1=18
x=17
=.= hok tốt!!
\(541+\left(218-x\right)=375.\)
\(\Leftrightarrow218-x=-166\)
\(\Leftrightarrow x=218-\left(-166\right)\)
\(\Leftrightarrow x=384\)
\(5.\left(x+35\right)=515\)
\(\Leftrightarrow x+35=103\)
\(\Leftrightarrow x=103-35\)
\(\Leftrightarrow x=68\)
\(10+2x=4^5:4\)
\(\Leftrightarrow10+2x=4^4\)
\(\Leftrightarrow10+2x=256\)
\(\Leftrightarrow2x=256-10\)
\(\Leftrightarrow2x=246\)
\(\Leftrightarrow x=123\)
\(96-3.\left(x+1\right)=42\)
\(\Leftrightarrow3.\left(x+1\right)=96-42\)
\(\Leftrightarrow3\left(x+1\right)=54\)
\(\Leftrightarrow x+1=54:3\)
\(\Leftrightarrow x+1=18\)
\(\Leftrightarrow x=17\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(541+\left(218-x\right)=375\)
\(\Leftrightarrow759-x=375\)
\(\Leftrightarrow x=384\)
2) \(5\cdot\left(x+35\right)=515\)
\(\Leftrightarrow x+35=103\)
\(\Rightarrow x=68\)
3) \(96-3\cdot\left(x+1\right)=42\)
\(\Leftrightarrow3\cdot\left(x+1\right)=54\)
\(\Leftrightarrow x+1=18\)
\(\Rightarrow x=17\)
4) \(2\cdot x-138=2^3\cdot3^2\)
\(\Leftrightarrow2\cdot x-138=72\)
\(\Leftrightarrow2\cdot x=210\)
\(\Rightarrow x=105\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(y+3\right)^2+\left(y-4\right)^2=0\)
Vì \(\left(x+3^2\right)\ge0;\left(y-4\right)^2\ge0\)nên \(\hept{\begin{cases}\left(x+3\right)^{^2}=0\\\left(y-4\right)^2=0\end{cases}}\)=>\(\hept{\begin{cases}x+3=0\\y-4=0\end{cases}}\)=>\(\hept{\begin{cases}x=-3\\y=4\end{cases}}\)
\(\left(x+3\right)^2+\left(y-4\right)^2=0\)
Vì \(\left(x+3\right)^2\ge0;\left(y-4\right)^2\ge0\)nên \(\hept{\begin{cases}\left(x+3\right)^2=0\\\left(y-4\right)^2-0\end{cases}}\)=>\(\hept{\begin{cases}x+3=0\\y-4=0\end{cases}}\)=>\(\hept{\begin{cases}x=-3\\y=4\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(3\left[35+\left(x+10\right)\right]-375=0\)
\(3\left(35+x+10\right)=375\)
\(x+45=125\)
\(x=80\)
b) \(2\left|x\right|-\left(-5\right)=7\)
\(2\left|x\right|+5=7\)
\(2\left|x\right|=2\)
\(\left|x\right|=1\)
\(\Rightarrow x\in\left\{1;-1\right\}\)
a) 3.[35+(x+10)]-375=0
3.[35+(x+10)] = 0+375
3.[35+(x+10)] = 375
35+(x+10) = 375:3
35+(x+10) = 125
x+10 = 125-35
x+10 = 90
x = 90-10
x = 80
Vậy x=80
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (3x-12) :8 +10= 13
<=> (3x-12):8 = 13-10 = 3
<=> 3x-12 = 3 .8 = 24
<=> 3x = 24+12=36
<=> x=36:3=12
b) (x+5).8-20 = 60
<=> (x+5) .8 = 60+20=80
<=> x+5 = 80:8 = 10
<=> x=10-5 = 5
c) 3.[35+(x-10)]-375 = 0
<=> 3.[35+(x-10)] = 0 +375=375
<=> 35+(x-10) = 375 :3 = 125
<=> x-10 = 125-35=90
<=> x = 90+10 = 100
d) ( 158x+173-24) :35 = 81
<=> 158x+149 = 81 . 35 = 2835
<=> 158x = 2835 -149= 2686
<=> x= 2686 : 158 = 17
e) x - 140 : 35 = 0
<=> x-4 = 0
<=> x=0+4 = 4
(3x - 12 ) : 8 + 10 = 13
(3x - 12 ) : 8 = 13 - 10 = 3
(3x - 12 ) = 3 x 8 = 24
3x = 24 - 12 = 12
x =13 : 3 = 4
( x + 5 )
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(|x-3|-x=2x-\frac{5}{3}\)
\(\Leftrightarrow|x-3|=3x-\frac{5}{3}\left(1\right)\)
Mà \(|x-3|\ge0;\forall x\)
\(\Rightarrow3x-\frac{5}{3}\ge0\)
\(\Rightarrow x\ge\frac{5}{9}\)
Từ (1) \(\Rightarrow\orbr{\begin{cases}x-3=3x-\frac{5}{3}\\x-3=\frac{5}{3}-3x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}-2x=\frac{4}{3}\\4x=\frac{14}{3}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{-2}{3}< \frac{5}{9}\left(loai\right)\\x=\frac{7}{6}>\frac{5}{9}\left(chon\right)\end{cases}}\)
Vậy \(x=\frac{7}{6}\)
3.[35+(x+10]-375=0
3.[35+(x+10)=375
35+(x+10)=125
x+10=90
x=90-10
x=80
3.[35+(x+10)]=0+375
3.[35+(x+10)]=375
35+(x+10)=375:3
35+(x+10)=125
x+10=125-35
x+10=90
x=90-10
x=80