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\(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}=\frac{x+2}{12^{12}}\frac{x+2}{13^{13}}\)
=> x + 2 = 0
=> x = 0 - 2
=> x = -2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{x+8}{12}+\dfrac{x+9}{11}+\dfrac{x+10}{10}+3=0\\ \Leftrightarrow\dfrac{x+8}{12}+1+\dfrac{x+9}{11}+1+\dfrac{x+10}{10}+1=0\\ \Leftrightarrow\dfrac{x+20}{12}+\dfrac{x+20}{11}+\dfrac{x+20}{10}=0\\ \Leftrightarrow\left(x+20\right)\left(\dfrac{1}{12}+\dfrac{1}{11}+\dfrac{1}{10}\right)=0\\ \Leftrightarrow x+20=0\Leftrightarrow x=-20\\ KL:...\)
`<=>((x+8)/12+1)+((x+9)/11+1)+((x+10)/10+1)=0`
`<=>(x+20)/12+(x+20)/11+(x+20)/10=0`
`<=>(x+20)(1/12+1/11+1/10)=0`
Vì `1/12+1/11+1/10 ≠ 0`
`=>x+20=0`
`=>x=0-20`
`=>x=-20`
![](https://rs.olm.vn/images/avt/0.png?1311)
Vì n+(-n)=0 nên ta có:
12+11+10+..............+x=12
=>12+(11+10+..+x)=12
=>11+10+...............+x=0
=>x=-11( vì -11+11=0 sau đó 10+-10=0;.............)
Vậy .........
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ta có 12+11+10+...+X=12\(\Leftrightarrow\)11+10+...+X=0(1)\(\Leftrightarrow\)(X+11).n/2=0(goi n la so so hang cua ve trai (1) n\(\ne\)0)
\(\Rightarrow\)X+11=0\(\Leftrightarrow\)X=-11
vậy X=-11
12 + 11 + 10 + ... +X = 12
=> 12 + 11 + 10 +.. + x - 12 = 0
=> 11 +10 + .. + X = 0
=> x = -11
![](https://rs.olm.vn/images/avt/0.png?1311)
12 + 11 + 10 +...+ x = 12
=> 11 + 10 +...+ x = 0
Gọi số số hạng của dãy là n (n thuộc N*)
Ta có:
(11 + x)n : 2 = 0
=> (11 + x)n = 0
Mà n khác 0
=> 11 + x = 0
=> x = -11
Vậy...
để 12+11+10+...+x=12
thì (11+10+...+x)=0
dựa vào tính chất cộng với số đối
=> x = 11
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a)\)
\(x+\frac{1}{10}+x+\frac{11}{11}=x+\frac{11}{12}\)
\(\Leftrightarrow x=\frac{11}{12}-\frac{1}{10}-\frac{11}{11}\)
\(\Leftrightarrow x=\frac{-11}{60}\)
\(b)\)
\(-\left|x-\frac{1}{2}\right|=\frac{1}{2}\)
\(\Leftrightarrow\left|x-\frac{1}{2}\right|=\frac{-1}{2}\) (Vô lý)
Vậy \(x\in\varnothing\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :\(\frac{x+8}{12}+\frac{x+9}{11}+\frac{x+10}{10}+3=0\)
=> \(\left(\frac{x+8}{12}+1\right)+\left(\frac{x+9}{11}+1\right)+\left(\frac{x+10}{10}+1\right)=0\)
=> \(\frac{x+20}{12}+\frac{x+20}{11}+\frac{x+20}{10}=0\)
=> \(\left(x+20\right)\left(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\right)=0\)
Vì \(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\ne0\)
=> x + 20 = 0
=> x = -20
Vậy x = -20
\(\frac{x+8}{12}+\frac{x+9}{11}+\frac{x+10}{10}+3=0\)
\(\Leftrightarrow\left(\frac{x+8}{12}+1\right)+\left(\frac{x+9}{11}+1\right)+\left(\frac{x+10}{10}+1\right)=0\)
\(\Leftrightarrow\frac{x+20}{12}+\frac{x+20}{11}+\frac{x+20}{10}=0\)
\(\Leftrightarrow\left(x+20\right)\left(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\right)=0\)
Vì \(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\ne0\)
\(\Rightarrow x+20=0\Rightarrow x=-20\)
78 + x = 12
=> x = -66
12 + 11 + 10 +....+ X = 12
11 + 10 + ...+ X = 12 - 12
(X + 11) . n : 2 = 0
X + 11 = 0
X = 0 + 11
X = 11
Vậy X = 11