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![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a: \(17-x=3\)
=>\(x=17-3\)
=>x=14(nhận)
b: \(2\cdot\left(x-1\right):3=6\)
=>\(2\left(x-1\right)=6\cdot3=18\)
=>x-1=18/2=9
=>x=9+1=10(nhận)
c: \(x+\left(-2\right)=\left(-11\right)+7\)
=>\(x-2=-4\)
=>\(x=-4+2=-2\left(loại\right)\)
d: \(\left(x-1\right)^2-5=20\)
=>\(\left(x-1\right)^2=25\)
=>\(\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\left(nhận\right)\\x=-4\left(loại\right)\end{matrix}\right.\)
Câu 3:
a: Đặt *=a
\(\overline{57a3}⋮9\)
=>\(5+7+a+3⋮9\)
=>\(a+15⋮3\)
mà 0<=a<=9
nên a=3
=>*=a
b: \(A=123\cdot7+8+9\)
123*7 là số lẻ
9 là số lẻ
=>123*7+9 chia hết cho 2
mà 8 chia hết cho 2
nên \(A=123\cdot7+9+8⋮2\)
\(123\cdot7⋮3;9⋮3;8⋮̸3\)
=>\(A=123\cdot7+9+8⋮̸3\)
c: \(B=3\cdot5\cdot7+10^{50}\)
\(=5\cdot3\cdot7+5\cdot5^{49}\cdot2^{49}\)
\(=5\left(3\cdot7+5^{49}\cdot2^{49}\right)⋮5\)
=>B là hợp số
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (68 - 8) . 14 + (-27 - 33) . 15
=60.14+(-60).15
=-60.(15-14)
=-60.1
=-60
b) 37 . (55 - 49) - 49 . (55 - 37)
=37.55-37.49-49.55-49.37
=37.55-49.55
=55(37-49)
=55.(-12)
=-660
c) (-4) . 19 . (-8) . (-25) . (125)
=[-4.(-25)].[-8.(-125)].19
=100.1000.19
=1900000
d) 32 . (-125) . 17 . (-25)
=(32.17).[-125.(-25)]
=544.3125
=1700000
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a)23+3 𝑥 =125 | b) 70 – 5.(𝑥 - 3)= 45 | c) 20 + 5 𝑥 = 57:55
3 𝑥 +23=125 | 70−5 𝑥 +15=45 | 5 𝑥 +20=5755
𝑥=34 | 𝑥=8 | 𝑥=−104
275
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a) ( -125) + 100 + 80 + 125 + 20
= [ ( -125)+125] + ( 80+20) + 100
= 0 + 100 + 100 = 200
b) 27 + 55 + (-17) + ( - 55)
= [ 27+(-17)] +[ 55+(-55)]
= 10 + 0 = 10
c) (-92) + (-251) + (-8) + 251
= [ (-92) + (-8)] + [ (-251)+251]
= (-100) + 0 = -100.
d) (-31) + (-95) +131 + (-5)
= [ (-31)+131] +[ (-95)+(-5)] = 100 + (-100) = 0
e) (187 - 23) - (20-180)
= 187 - 23 - 20 + 180 = (187-180) - (23-20) = 7 - 3 = 4
g) (-50+19+143) - (-79+25+48)
= -50+19+143 + 79 - 25 - 48
= [ -50-25] + (19 + 79) + 143 - 48
= -75 + 98 + 143 - 48 = 143 - 75 + ( 98 -48)
= 68 + 50 = 118
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5^5.\dfrac{1}{20}.2^2.3^3:125\)
\(=5^5.\dfrac{1}{2^2.5}.2^2.3^3:5^3\)
\(=\dfrac{2^2.3^3.5^5}{2^2.5^4}=3^3.5=27.5=135\)
= 3125 x 1/20 x 4 x 27 : 125
= 625/4 x 4 x 27 : 125
= 625 x 27 : 125
= 16875 : 125
= 135
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (-125) + 100 + 80 + 125 + 20
= [(-125) + 125] + (80 + 20) + 100
= 0 + 100 + 100
= 200
b) 27 + 55 + (-17) + (-55)
= [27 + (-17)] + [55 + (-55)]
= (27 - 17) + 0
= 10
c) (-92) + (-251) + (-8) + 251
= [(-251) + 251] + [(-92) + (-8)]
= 0 - 100
= -100
d) (-31) + (-95) + 131 + (-5)
= [(-31) + 131) + [(-95) + (-5)]
= 100 + (-100)
= 0
Hok tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài làm
a) 15 x 18
= 15 x 2 x 9
= 30 x 9
= 27
b) 25 × 24
= 25 x 4 x 6
= 100 x 6
= 600
c) 125 × 72
= 125 x 8 x 9
= 1000 x 9
= 9000
d) 55 × 14
= 5 x 11 x 2 x 7
= ( 5 x 2 ) x ( 11 x 7 )
= 10 x 77
= 770
# Học tốt #
15 x 18 = 270
25 x 24 = 600
125 x 72 = 9000
55 x 14 = 770
a: Ta có: 7x+55=125
\(\Leftrightarrow7x=70\)
hay x=10
b: Ta có: \(55-\left(19-x\right)=125\)
\(\Leftrightarrow55-19+x=125\)
hay x=89