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A) \(y=5X-\frac{18.2}{18}=135X-2=13x=3\)
B)\(y=\frac{5x-36}{18}=13\frac{5x}{18}-2=13\frac{5x}{18}=15\frac{x}{18}=3x=54\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 5x – 36 : 18 = 13
5x – 2 = 13
5x = 13+2
5x = 15
x = 15 :5
x = 3
Vậy x = 3
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c) (5x – 36) : 18 = 13
(5x – 36) = 13.18
(5x – 36) = 234
5x = 234 + 36
5x = 270
x = 270:5
x = 54
Vậy x = 54
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1) \(x-36:18=12\)
\(\Rightarrow x-2=12\)
\(\Rightarrow x=14\)
2) \(\left(x-36\right):18=12\)
\(\Rightarrow x-36=216\)
\(\Rightarrow x=252\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(\Rightarrow5x-36=216\)
\(\Rightarrow5x=252\Rightarrow x=\dfrac{252}{5}\)
2) \(\Rightarrow\left[{}\begin{matrix}x-890=0\\74-x=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=890\\x=74\end{matrix}\right.\)
(5x-36):18=12
5x-36=216
5x=252
x=50,4
(x-890)(74-x)=0
=> x-890=0 hoặc 74-x=0
x=890 hoặc x=74
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b: Ta có: 7x-8=713
nên 7x=721
hay x=103
c: Ta có: x-36:18=12
nên x-2=12
hay x=14
d: Ta có: (x-36):18=12
nên x-36=216
hay x=252
Tìm x
( 5x - 36 ) : 18 = 13
=> 5x - 36 = 234
=> 5x = 234 + 36
=> 5x = 270
=> x = 270 : 5
=> x = 54
\(\left(5x-36\right):18=13\)
\(5x-36=13.18\)
\(5x-36=234\)
\(5x=234+36\)
\(5x=270\)
\(x=\frac{270}{5}\)
\(x=54\)