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4.120+[45:9+15(x+1)]=500
=>480+[5+15(x+1)]=500
=>5+15(x+1)=20
=>15(x+1)=15
=>x+1=1
=>x=0
4.120+[45:9+15(x+1)]=500
480+[5+15x+15]=500
480+5+15x+15=500
500+15x=500
15x=0
x=0
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a: \(\Leftrightarrow5x-42=251\)
=>5x=293
hay x=293/5
b: \(\Leftrightarrow20-x=20\)
hay x=0
c: \(\Leftrightarrow x-4300-\dfrac{1}{50}=4250\)
\(\Leftrightarrow x=\dfrac{427501}{50}\)
d: =>(x+200):4=460-340=120
=>x+200=480
hay x=280
e: =>5+15(x+1)=500-480=20
=>15(x+1)=15
=>x+1=1
hay x=0
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4 . 120 + [45 : 9 +15 . (x + 1) = 500
480 + [45 : 9 +15 . (x + 1) = 500
45 : 9 +15 . (x + 1) = 500-480
45 : 9 +15 . (x + 1) = 20
5 +15 . (x + 1) = 20
15 . (x + 1) = 20-5
15 . (x + 1) = 15
x + 1=15:15
x + 1=1
x=1-1
x=0
![](https://rs.olm.vn/images/avt/0.png?1311)
=>480 + [ 5 + 15 . (x + 1) = 500
15 . ( x + 1 )=500 - 480 - 5 = 15
x + 1 =15 : 15 =1
x =1 - 1
x = 0
vay x =0
k nha
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1
Theo đề bài ta có:
x chia hết cho 15
x chia hết cho 180
=>x=BC(15,180)
15=3.5
180=22.32.5
BCNN(15,180)=22.32.5=4.9.5=180
BC(15,180)=B(180)={0;180;360;540;...}
=>x thuộc {0;180;360;540;...}
Bài này hok khó lắm đâu,chịu suy nghĩ 1 lát là làm đc ấy mà
4.120+[45:9+15-(x+1)]=500
480+[45:9+15-(x+1)]=500
45:9+15-(x+1)=500-480
45:9+15-(x+1)=20
5+15-(x+1)=20
20-(x+1)=20
x+1=20-20
x+1=0
x=0-1
x=-1
=>4.120+[45:9+15-(x+1)]=500
=>480+[45:9+15-(x+1)]=500
=>45:9+15-(x+1)=500-480
=>45:9+15-(x+1)=20
=>5+15-(x+1)=20
=>20-(x+1)=20
=>x+1=20-20
=>x+1=0
=>x=0-1
=> x=-1