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a, 1230 : 3(x – 20) = 10
3(x – 20) = 123
x – 20 = 41
x = 61
b, 250 – 10.(24 – 3x):15 = 244
10.(24 – 3x):15 = 6
10.(24 – 3x) = 90
24 – 3x = 9
3x = 15
x = 5
c, 4 x 3 + 15 = 47
4 x 3 = 32
x 3 = 8 = 2 3
x = 2
d, 65 - 4 x + 2 = 2014 0
65 - 4 x + 2 = 1
4 x + 2 = 64 = 4 3
x + 2 = 3
x = 1
e, 4 . 2 x - 3 = 125
4 . 2 x = 128
2 x = 32 = 2 5
x = 5
![](https://rs.olm.vn/images/avt/0.png?1311)
4.2x – 3 = 125
4.2x = 125 + 3
4.2x = 128
2x = 128 : 4
2x = 32
2x = 25
x = 5
Vậy x = 5
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 4x3+15=47
=> 4x3=47-15
=> 4x3=32
=> x3=32:4
=> x3=23
=> x=2
b) 4.2x-3=125
=> 4.2x=125+3
=> 2x=128:4
=> 2x=32
=> 2x=25
=> x=5
4x3 + 15 = 47
4x3 = 47 - 15
4x3 = 32
x3 = 32 : 4
x3 = 8
x3 = 23
x = 2
b) 4 . 2x - 3 = 125
4 . 2x = 125 + 3
4 . 2x = 128
2x = 128 : 4
2x = 32
2x = 25
x = 5
![](https://rs.olm.vn/images/avt/0.png?1311)
4.2^x-3=125
4.2^x = 125 + 3
4.2^x = 128
2^x = 128 : 4
2^x = 32
=> 2^x = 2^5
=> x = 5
Vậy x = 5
4x3+15=47=>4x3=32=>x3=8=>x3=23=>x=2
4.2^x-3=125
4.2^x = 125 + 3
4.2^x = 128
2^x = 128 : 4
2^x = 32
=> 2^x = 2^5
=> x = 5
Vậy x = 5
4x3+15=47=>4x3=32=>x3=8=>x3=23=>x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(4\cdot x^3+15=47\) \(4\cdot2^x-3=125\)
\(4x^3=47-15\) \(4\cdot2^x=125+3\)
\(4x^3=32\) \(4\cdot2^x=128\)
\(x^3=32:4\) \(2^x=128:4\)
\(x^3=8\) \(2^x=32\)
\(x^3=2^3\) \(2^x=2^5\)
\(\Rightarrow x=2\) \(\Rightarrow x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)4x3+15=47
4x3=47-15
4x3=32
x3=32:4
x3=8
x3=23
vậy x = 2
b)4.2x-3=125
4.2x=125+3
4.2x=128
2x=128:4
2x=32
2x=25
Vậy x=5
a) 4x3 + 15 = 47 b) 4.2x - 3 = 125
4x3 = 47 - 15 4.2x = 125 + 3
4x3 = 32 4.2x = 128
x3 = 32 : 4 2x = 128 : 4
x3 = 8 2x = 32
x3 = 23 2x = 25
=> x = 2 => x = 5
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: 2 x + 1 3 = 3 3 nên 2x + l = 3. Do đó x = l.
b) Ta có: 2 x - 1 3 = 5 3 nên 2x - 1 = 5. Do đó x = 3.
c) Ta có: x + 1 4 = 2 x 4 nên x +1 = 2x. Do đó x = 1.
d) Ta có: 2 x - 1 5 = x 5 nên 2x - l = x. Do đó x = l
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