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a, 3 - 2x = 3 . (5 - x) + 4
3 - 2x = 15 - 3x + 4
-2x + 3x = 15 + 4 - 3
x = 16
b, 4 - (7x + 2017) = 6 . (5 - x) - 2017
4 - 7x - 2017 = 30 - 6x - 2017
-7x + 6x = 30 - 2017 - 4 + 2017
-x = 26
x = -26
c, 15 - x . (x + 1) = 4 - x^2 + 2x
15 - x^2 - x = 4 - x^2 + 2x
-x^2 - x + x^2 - 2x = 4 - 15
-3x = -11
x = 11/3
d, -4 . (x - 5) + 2016 = 3 . (8 - x) - (2x - 2016)
-4x + 20 + 2016 = 24 - 3x - 2x + 2016
-4x + 3x +2x = 24 + 2016 - 20 - 2016
x = 4
đúng 100%
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Ta có:
x biết: 2016 x 2016 - 2015 x 2017 + x = 2016
x = 2015 x 2017 + 2016 - 2016 x 2016
x = 2015 x 2017 + 2016 x (1 - 2016)
x = 2015 x 2017 - 2015 x 2016
x = 2015 x (2017 - 2016)
x = 2015 x 1
x = 2015
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Có: \(\left(x-1\right)^{2016}\ge0\forall x;\left|y+3\right|\ge0\forall y\)
\(\Rightarrow B=\left(x-1\right)^{2016}+\left|y+3\right|+2017\ge2017\)
Dấu ''='' xảy ra khi \(\begin{cases}\left(x-1\right)^{2016}=0\\\left|y+3\right|=0\end{cases}\)\(\Rightarrow\begin{cases}x-1=0\\y+3=0\end{cases}\)\(\Rightarrow\begin{cases}x=1\\y=-3\end{cases}\)
Vậy GTNN của B là 2017 khi x = 1; y = -3
\(B=\left(x-1\right)^{2016}+\left|y+3\right|+2017\)
Vì: \(\left(x-1\right)^{2016}\ge0;\left|y+3\right|\ge0\)
=> \(\left(x-1\right)^{2016}+\left|y+3\right|\ge0\)
=> \(\left(x-1\right)^{2016}+\left|y+3\right|+2017\ge2017\)
Vậy GTNN của B là 2017 khi x=1;y=-3
![](https://rs.olm.vn/images/avt/0.png?1311)
câu 1. tìm x nguyên để \(\frac{-35}{6}\)<x<\(\frac{-18}{5}\)
<=> -4,375<x<-3,6
mà x\(\in\)Z nên x={-4}
câu 2. A=\(\frac{2015}{2016}\)+\(\frac{2016}{2017}\)
B=\(\frac{2015+2016}{2016+2017}\)=\(\frac{2015}{2016+2017}\)+\(\frac{2016}{2016+2017}\)
Vì \(\frac{2015}{2016+2017}\)<\(\frac{2015}{2016}\); \(\frac{2016}{2016+2017}\)<\(\frac{2016}{2017}\)
Vậy B<A
\(\left(x-1\right)^{2016}\ge0\)
\(\left|y+3\right|\ge0\)
\(\left(x-1\right)^{2016}+\left|y+3\right|+2017\ge2017\)
\(MinB=2017\Leftrightarrow x=1;y=-3\)