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![](https://rs.olm.vn/images/avt/0.png?1311)
a) Từ hàm số y= 7/2x, ta có :
- 7/5=7/2 .a
-14 = 35a
a = -14/35
a = - 0,4
b) Từ phương trình y=1/7 x, ta có :
b = 1/7.0,35
b = 0,05
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
a. Để $A(a,\frac{-7}{5})$ thuộc đths thì:
$y_A=\frac{7}{2}x_A$
$\Rightarrow \frac{-7}{5}=\frac{7}{2}a$
$\Rightarrow a=\frac{-7}{5}: \frac{7}{2}=\frac{-2}{5}$
b.
Để $B(0,35; b)$ thuộc đths thì:
$y_B=\frac{1}{7}x_B$
$\Rightarrow b=\frac{1}{7}.0,35=0,05$
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Từ hàm số y= 7/2x, ta có
- 7/5=7/2 .a
-14 = 35a
a = -14/35
a = - 0,4
b) Từ phương trinh y=1/7 x, ta có:
b = 1/7.0,35
b = 0,05
a) Thay số: \(\frac{-7}{5}\)= \(\frac{7}{2}\). a \(\Rightarrow\)a= \(\frac{7}{2}\): \(\frac{-7}{5}\)= \(\frac{-2}{5}\)= -0,4
b) Thay số: b= \(\frac{1}{7}\). 0,35= 0,35 : 7= 0,05
![](https://rs.olm.vn/images/avt/0.png?1311)
câu a : vì A(a; -1,4 ) thuộc hàm số y = 3,5x
nên a= -1,4 : 3,5= -0,4
câu b : vì B( 0,35; b ) thuộc hàm số y= 1/7x
nên b = 0,35 . 1/7= 0,05.
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 9:
b: Điểm A thuộc đồ thị vì \(y_A=4=-2\cdot\left(-2\right)=-2\cdot x_A\)
Bài 10:
a: Thay x=1 và y=-3 vào (d), ta được:
\(a\cdot1=-3\)
hay a=-3
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án:
Giải thích các bước giải:
a)Gọi a là x ta có:
x=-5×(-7/5)=-7
ta được A(-7; -7/5)
b)gọi b là y ta có
y=2×0,35=0,7
Ta được B(0,35; 0;7)
![](https://rs.olm.vn/images/avt/0.png?1311)
Điểm B(0,35; b) thuộc đồ thị hàm số nên khi x = 0,35 ta có y = b.
Suy ra:
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a)từ hám số y=7/2x ta có
-7/5=7/2*a
-14=35*a
a= -14:35
a=0,4
b) từ phương trình y=1/7x ta có
b=1/7*0,35
b=0,05
chúc bạn hok tốt