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Ta có \(\frac{x-3}{y-2}=\frac{3}{2}\)
Nên 2 ( x - 3 ) = 3 ( y - 2 )
Do đó 2x - 6 = 3y - 6 nên 2x = 3y
Suy ra 2x - 2y = y hay 2 ( x - y ) = y
Mà x - y = 4 nên 2.4 = y
Suy ra y = 8
\(x=\frac{3y}{2}=\frac{3.8}{2}=12\)
Vây x = 12 ; y = 8
\(\frac{x-3}{y-2}=\frac{3}{2}\)
=> \(\left(x-3\right).2=3\left(y-2\right)\)
=> \(2x-6=3y-6\)
=> \(2x=3y\)
Khi đó ,ta có: x - y = 4
=> 2(x - y) = 8
=> 2x - 2y = 8
=> 3y - 2y = 8
=> y = 8
=> x = 4 + 8 = 12
Vậy x = 12 và y = 8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-3}{y-2}=\frac{3}{2}\)
=> 2. ( x - 3 ) = 3.( y - 2 )
=> 2x - 6 = 3y - 6
=> 2x = 3y
=> \(\frac{x}{3}=\frac{y}{2}\)
Áp dụng tính chất dãy tỉ số bằng nhau.
=> \(\frac{x}{3}=\frac{y}{2}=\frac{x-y}{3-2}\)\(=\frac{4}{1}=4\)
=> \(\hept{\begin{cases}x=3.4=12\\y=2.4=8\end{cases}}\)
Vậy x = 8, y = 12
ta có:\(\frac{x-3}{y-2}=\frac{3}{2}\)
\(\Rightarrow\frac{x-3}{3}=\frac{y-2}{2}=\frac{x-3-y+2}{3-2}=\frac{\left(x-y\right)-\left(3-2\right)}{1}=\frac{4-1}{1}=3\)
=> x-3/3 = 3 => x-3 = 9 => x = 12
y-2/2 = 3 => y-2 = 6=> y = 8
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{x-3}{y-2}=\frac{3}{2}\)
=> (x - 3) . 2 = (y - 2) . 3
=> 2x - 6 = 3y - 6
=> 2x = 3y
=> x = 3/2y
Khi đó, ta có: x - y = 4
hay 3/2y - y = 4
=> 1/2y = 4
=> y = 4 : 1/2
=> y = 8
=> x = 4 + 8 = 12
Vậy x = 12 và y = 8
Theo đề:\(\frac{x-3}{y-2}=\frac{3}{2}\Rightarrow2\left(x-3\right)=3\left(y-2\right)\)
\(\Rightarrow2x-6=3y-6\)
\(\Rightarrow2y-3y=-6+6\)
Vì\(x-y=4\Rightarrow x=4+y\)
\(\Rightarrow2\left(y+4\right)-3y=0\)
\(\Rightarrow2y+8-3y=0\)
\(\Rightarrow-y=-8\Rightarrow y=8\)
\(\Rightarrow x=y+4=8+4=12\)
Vậy y=8;x=12
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-3}{y-2}=\frac{3}{2}=\frac{x-3+3}{y-2+2}=\frac{x}{y}\)
\(\Rightarrow\frac{x}{3}=\frac{y}{2}=\frac{x-y}{3-2}=\frac{4}{1}=4\)
=>x=12;y=8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-2}{27}+\frac{x-3}{26}+\frac{x-4}{25}+\frac{x-5}{24}+\frac{x-44}{5}=1\)
\(\Leftrightarrow\left(\frac{x-2}{27}-1\right)+\left(\frac{x-3}{26}-1\right)+\left(\frac{x-4}{25}-1\right)+\left(\frac{x-5}{24}-1\right)\)\(+\left(\frac{x-44}{5}+3\right)=1-1\)
\(\Leftrightarrow\frac{x-29}{27}+\frac{x-29}{26}+\frac{x-29}{25}+\frac{x-29}{24}\)\(+\frac{x-29}{5}=0\)
\(\Leftrightarrow\left(x-29\right)\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\right)=0\)
Mà \(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\ne0\)
=> x - 29 = 0
=> x = 29.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-3}{y-2}=\frac{3}{2}\Rightarrow2x-6=3y-6\)
\(\Rightarrow2x-6+6=3y\)
\(\Rightarrow2x=3y\Rightarrow\frac{x}{3}=\frac{y}{2}\)
Theo t)c của dãy tỉ số bằng nhau :
\(\Rightarrow\frac{x}{3}=\frac{y}{2}=\frac{x-y}{3-2}=\frac{4}{1}=4\)
\(\Rightarrow x=4.3=12;y=4.2=8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
\(\frac{x-3}{y-2}=\frac{3}{2}\)
\(\Rightarrow2\left(x-3\right)=3\left(y-2\right)\)
\(\Rightarrow2x-6=3y-6\)
\(\Rightarrow2x-3y=6-6\)
\(\Rightarrow2x-3y=0\)
Vì \(x-y=4\)\(\Rightarrow\)\(x=4+y\)
\(\Rightarrow2\left(4+y\right)-3y=0\)
\(\Rightarrow8+2y-3y=0\)
\(\Rightarrow8-y=0\)
\(\Rightarrow y=8\)
Lại có : \(x=4+y\)
\(\Rightarrow x=4+8\)
\(\Rightarrow x=12\)
Vậy x = 12 và y = 8
_Chúc bạn học tốt_
\(\frac{x-3}{y-2}=\frac{3}{2}\)
\(\Leftrightarrow\left(x-3\right)2=\left(y-2\right)3\)
\(\Leftrightarrow2x-6=3y-6\)
\(\Leftrightarrow\left(2x-6\right)-\left(3y-6\right)=0\)
\(\Leftrightarrow2x-6-3y+6=0\)
\(\Leftrightarrow\left(2x-3y\right)-\left(6+6\right)=0\)
\(\Leftrightarrow\left(2x-3y\right)-12=0\)
\(\Leftrightarrow2x-3y=12\)
X=12
Y=8
Nha banj
\(\frac{x-3}{y-2}=\frac{3}{2}\) nên 2(x-3)=3(x-2)
Do đó 2x-6=3y-6 nên 2x=3y
=>2x-2y=y hay 2(x-y)=y
Nên 2.4=y
Vậy y=8 và x=\(\frac{3y}{2}=\frac{3.8}{2}=12\)