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\(a\cdot\frac{1}{5}+80\%\cdot a=20152015,15\)
\(\Rightarrow a\cdot\frac{1}{5}+\frac{4}{5}\cdot a=20152015,15\)
\(\Rightarrow a\cdot\left(\frac{1}{5}+\frac{4}{5}\right)=20152015,15\)
\(\Rightarrow a\cdot1=20152015,15\Rightarrow a=20152015,15:1=20152015,15\)
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a) 156 - 2 . x = 80
2 . x = 156 - 80
2 . x = 76
x= 76 : 2
x = 38
b) 315 + 5 . x = 200
5 . x = 200 - 315
5 . x = -115
x= -115 : 5
x = -23
c) 5 . ( x + 3 ) - 20 = 40
5 . ( x +3) = 40+20
5. ( x + 3) =60
x +3 =60:5
x + 3= 12
x = 12 - 3
x =9
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\(\frac{3+5+7+...+2015}{2+4+6+...+2014}+x=1\)
\(\frac{\left(3+2015\right).\left[\left(2015-3\right):2+1\right]:2}{\left(2+2014\right).\left[\left(2014-2\right):2+1\right]:2}+x=1\)
\(\frac{1016063}{1015056}+x=1\)
\(x=1-\frac{1016063}{1015056}\)
\(x=-\frac{1}{1008}\)
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\(A=\dfrac{1}{1\times4}+\dfrac{1}{4\times7}+\dfrac{1}{7\times10}+...+\dfrac{1}{100\times103}\)
\(=\dfrac{1}{3}\left(\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+...+\dfrac{3}{100\times103}\right)\)
\(=\dfrac{1}{3}\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{100}-\dfrac{1}{103}\right)\)
\(=\dfrac{1}{3}\left(1-\dfrac{1}{103}\right)=\dfrac{1}{3}.\dfrac{102}{103}=\dfrac{34}{103}\)
=>a*0,2+0,8*a=0,15
=>a=0,15