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![](https://rs.olm.vn/images/avt/0.png?1311)
25-[50-(2^3.17-2^3.14)]
=25-[50-(8.17-8.14)]
=25-[50-(136-112)]
=25-[50-24]
=25-26
=-1
|-128|: [45^2-(2010-2008.1^2010)]
=128:[45^2-(2010-2008.1)]
=128:[45^2-(2010-2008)]
=128:[45^2-2]
=128:[2025-2]
=128:2023
=0,063 (chắc mik làm sai b đấy :( )
25-[50-(2^3.17-2^3.14)]=25-{50-[2^3.(17-14)]}
=25-{50-[8.3]}
=25-{50-24}
![](https://rs.olm.vn/images/avt/0.png?1311)
(2010-2009+2008-2007+...+2-1):(-5)
=[(2010-2009)+(2008-2007)+...+(2-1)):(-5)
=(1+1+...+1):(-5)
Từ 1 đến 2010 có:(2010-1):1+1=2010 số
Vậy:có 2010:2=1005 số 1
=1005:(-5)
= -201
![](https://rs.olm.vn/images/avt/0.png?1311)
(1 + 2 + 3 + 4 + ... + 2010).(1 + 22 + 33 + ... + 20102010 + 20112011).(170170 - 7.11.13.170)
= (1 + 2 + 3 + 4 + ... + 2010).(1 + 22 + 33 + ... + 20102010 + 20112011).(170170 - 170170)
= (1 + 2 + 3 + 4 + ... + 2010).(1 + 22 + 33 + ... + 20102010 + 20112011). 0
= 0
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : ( 1 + 2 + 3 +...+ 2010 ) . ( 1 + 2^2 + 3^3 + ... + 2010^2010 + 2011^2011 ) . ( 17017 - 7 . 11 . 13 . 17 )
= A . B . ( 17017 - 77 . 221 )
= A . B . ( 17017 - 17017 )
= A . B . 0
= 0
Tham khảo cách của mk nhé !
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a)\)
\(\left(-31\right)+\left(50-19\right)-\left(150-31\right)\)
\(=\left(-31\right)+50-19-150+31\)
\(=\left(-150\right)-19\)
\(=-169\)
\(b)\)
\(25.\left(45-17\right)-45.\left(25-17\right)\)
\(=25.45-25.17-45.25+45.17\)
\(=0\)
\(c)\)
\(\frac{-1}{12}+\frac{4}{3}=\frac{5}{4}\)
\(d)\)
\(3+\frac{-5}{20}+\frac{30}{75}+\frac{-7}{4}\)
\(=\left(\frac{3}{5}+\frac{30}{75}\right)-\left(\frac{5}{20}+\frac{7}{4}\right)\)
\(=1-2\)
\(=-1\)
a) (-31)+(50-19)-(150-31)
= (-31)+50+(-19)-150+(-31)
= (-31)+50-150+(-19)-(-31)
= (-31)+(-100)+12
= -119
b) 25(45-17)-45(25-17)
= 25.45-25.17-45.25-45.17
= 25(45-45)-25(17-17)
= 0
c) -1/12 + 4/3
= -1/12 + 16/12
= 15/12
= 5/4
d) 3/5+(-5)/20+30/75+(-7)/4
= 45/75+30/75+(-5)/20+(-35)/20
= 1+(-2)
= -1
![](https://rs.olm.vn/images/avt/0.png?1311)
b) |-128| : [ 45 2 – ( 2010 - 2008 0 . 1 2010 )]
= 128 : [ 2025 – ( 2010 – 1 . 1 )] = 128 : ( 2025 – 2009 ) = 128 : 16 = 8
a) 25 –[ 50 – ( 2 3 . 17 – 2 3 . 14 )]
= 25 – ( 50 – 23 . 3 ) = 25 – ( 50 – 24 )
= 25 – 26 = -1
b) |-128| : [ 45 2 – ( 2010 – 2008 0 . 1 2010 )]
= 128 : [ 2025 – ( 2010 – 1 . 1 )] = 128 : ( 2025 – 2009 ) = 128 : 16 = 8