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a) 118 - 26 + 76 - 18
= 92 + 58
= 150
b) 45 - 36 : 32
= 45 - 4
= 41
c) 90 : {[52 - ( 42 - 5 )] . 3 }
= 90 : [( 52 - 37 ) . 3]
= 90 : ( 15 . 3 )
= 90 : 45
= 2
a 118-26=76-18=(118-18)+76-26)=150
b45-36:3 mũ 2 = 45-9=41
c (mình ghi giấu ngoặc ko dc nha bn) kết quả =90:(52-37).3=90:15.3=18
K MIK NHA BN
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a) 1-3+5-7+9-12+15-18
= (1+ 9) - (3+7) + (5+15) - (12+18)
= 10 - 10 + 20 - 30 = -10.
b) (-2)+5-7+9-11+13-15+19-21
= 5 - 11 - 2 -2 = 5 - (11+2+2)
= 5 - 15 = -10
Bài 1:
a) Ta có: 1-3+5-7+9-12+15-18
=(1+9)-(3+7)+(5+15)-(12+18)
=10-10+20-30
=-10
b) Ta có: \(\left(-2\right)+5-7+9-11+13-15+19-21\)
\(=3+2+2+4-21\)
\(=5+6-21\)
=11-21=-10
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a: =>x-35=-23
=>x=12
b: =>|x-8|=13
=>x-8=13 hoặc x-8=-13
=>x=21 hoặc x=-5
Bài 1:
a: =42-98-42+12-12=-98
b: =10x4x3x(-25)=40x(-25)x3=-1000x3=-3000
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a) \(\dfrac{3}{10}\)
b) \(\dfrac{9}{28}\)
c) \(\dfrac{88}{195}\)
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b: =-45-27+8=-72+8=-64
c: =12:6=2
d: =-24:8=-3
e: =-36:9=-4
f: =14:7=2
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\(a,3^3+3^2-\left(2^7:2^5+7^8:7^7\right)=27+9-\left(2^2+7\right)=36-11=25\)
\(b,27.77+27.27-27=27\left(77+27-1\right)=27.103=2781\)
\(c,52:\left(43-30\right)+144-16=52:13+128=4+128=132\)
\(f,3^2.101-3^2.101^0=3^2\left(101-101^0\right)=9\left(101-1\right)=9.100=900\)
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\(a,\dfrac{2}{3}-\dfrac{5}{6}+\dfrac{3}{4}\)
\(=(\dfrac{2}{3}+\dfrac{3}{4})-\dfrac{5}{6}\)
\(=\dfrac{7}{12}\)
\(b,\dfrac{6}{7}.\dfrac{8}{13}+\dfrac{6}{13}.\dfrac{9}{7}-\dfrac{-4}{13}.\dfrac{6}{7}\)
\(=\dfrac{6}{7}.(\dfrac{8}{13}-\dfrac{4}{13})+(\dfrac{6}{13}.\dfrac{9}{7})\)
\(=(\dfrac{6}{7}.\dfrac{4}{13})+\dfrac{54}{91}\)
\(=\dfrac{24}{91}+\dfrac{54}{91}\)
\(=\dfrac{78}{91}=\dfrac{6}{7}\)
\(c,19.(-26)\)
\(=-494\)
a) `2/3 - 5/6 +3/4`
`=4/6-5/6+3/4`
`=-1/6+3/4`
`=-4/24+18/24`
`=14/24=7/12`
b) `6/7 .8/13 +6/13 .9/7 -4/13 .6/7`
`=6/7 .(8/13-4/13) + 6/13 .9/7`
`=6/7 . 4/13 + 6/13 . 9/7`
`= 6/13 .4/7 +6/13 .9/7`
`=6/13 . (4/7+9/7)`
`=6/13 . 13/7`
`=6/7`
c) `19.(-26)`
`=(1-20).(20+6)`
`=20+6-400-120`
`=-494`
a)\(118-26+76-18=92+76-18=168-18=150\)
b)\(45-36\div3^2=45-36\div9=45-4=41\)
c)\(90\div\left[52-\left(42-5\right).3\right]=90:\left[52-37.3\right]=90:\left[52-111\right]\)
\(=90:\left(-59\right)=\frac{-90}{59}\)
nhabinn2011![](/images/avt/avt4/avt680904_60by60.jpg)
a, 118 - 26 + 76 - 18
= 92 + 76 - 18
= 168 - 18
= 150
b, 45 - 36 : 3\(^2\)
= 45 - 36 : 9
- 45 - 4
= 41
c, 90 : { 52 - ( 42 - 5 ) . 3 }
= 90 : { 52 - 37 . 3 }
= 90 : { 52 - 111 }
Đến đây thì bạn bị lộn đề phần c rồi.