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20 tháng 4 2018

\(B=\dfrac{3^2.4^2.2^{18}}{11.2^{13}.2^{22}-2^{36}}\)

\(B=\dfrac{3^2.2^{22}}{2^{35}\left(11-2\right)}\)

\(B=\dfrac{3^2}{2^{13}.9}\)

\(B=\dfrac{1}{2^{13}}=\dfrac{1}{8129}\)

\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot9}=2\)

8 tháng 1

\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\dfrac{\left(3.2^2.2^{16}\right)^2}{11.2^2.\left(2^2\right).11-\left(2^4\right)^9}\)

\(=\dfrac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^2.2^{22}-2^{36}}\)

\(=\dfrac{3^2.2^4.2^{32}}{11.2^{24}-2^{36}}\)

\(=\dfrac{3^2.2^{34}}{11.2^{24}-2^{36}}\)

\(=\dfrac{3^2.2^{24}.2^{10}}{11.2^{24}-2^{12}.2^{24}}\)

\(=\dfrac{3^2.2^{24}.2^{10}}{\left(11-2^{12}\right).2^{24}}\)

\(=\dfrac{3^2.2^{10}}{11-2^{12}}\)

14 tháng 3 2018

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{35}.2}\)

\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)

\(=\frac{9.2^{35}.2}{2^{35}.9}\)

\(=2\)

14 tháng 3 2018

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(\frac{3^2.4^2.2^{32}}{11.2^{35}-2^{35}.2}\)

\(\frac{3^2.2^4.2^{32}}{2^{35}.\left(11-2\right)}\)

\(\frac{3^2.2^{36}}{2^{35}.9}\)

\(\frac{9.2^{35}.2}{2^{35}.9}\)

\(2\)

1 tháng 2 2019

a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)

   =1

b)=(1.2.3....8).(9-1-8)

   =(1.2.3....8).0

   =0

mik chỉ giải được zậy thôi.

t mik nha.

\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^3\cdot2^{22}-2^{36}}\)

\(=\dfrac{3^2\cdot2^{36}}{2^{25}\left(11-2^{11}\right)}=\dfrac{3^2\cdot2^{11}}{11-2048}=\dfrac{-3\cdot2^{11}}{679}\)

27 tháng 2 2023

\(\dfrac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^9}=\dfrac{\left(3\cdot2^2\cdot2^{16}\right)^2}{11\cdot2^2\cdot\left(2^2\right)^{11}-\left(2^4\right)^9}\)

\(=\dfrac{3^2\cdot\left(2^2\right)^2\cdot\left(2^{16}\right)^2}{11\cdot2^2\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^4\cdot2^{32}}{11\cdot2^{24}-2^{36}}\)

\(=\dfrac{3^2\cdot2^{34}}{11\cdot2^{24}-2^{36}}=\dfrac{3^2\cdot2^{24}\cdot2^{10}}{11\cdot2^{24}-2^{12}\cdot2^{24}}\)

\(=\dfrac{3^2\cdot2^{24}\cdot2^{10}}{\left(11-2^{12}\right)\cdot2^{24}}=\dfrac{3^2\cdot2^{10}}{11-2^{12}}\)

 

15 tháng 7 2017

\(B=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3.2^2.2^{16.2}}{11.2^{13}.2^{22}-2^{36}}=\frac{3.2^{34}}{11.2^{35}-2^{36}}=\frac{3.2^{34}}{2^{34}\left(11.2-2^2\right)}\)

\(=\frac{3}{11.2-2^2}=\frac{3}{11.2-4}=\frac{3}{22-4}=\frac{3}{18}=\frac{1}{6}\)

15 tháng 7 2017

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