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\(\dfrac{x}{2}-\dfrac{2}{9}=\dfrac{3}{2}-\left(\dfrac{-5}{4}\right)\\ \Rightarrow\dfrac{x}{2}-\dfrac{2}{9}=\dfrac{11}{4}\\ \Rightarrow\dfrac{x}{2}=\dfrac{11}{4}+\dfrac{2}{9}\\ \Rightarrow\dfrac{x}{2}=\dfrac{107}{36}\)
\(\Rightarrow x=\dfrac{107}{36}\times2\\ \Rightarrow x=\dfrac{107}{18}\)
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Ta có : \(x-\frac{3}{1.5}-\frac{3}{5.9}-\frac{3}{9.13}-\frac{3}{13.17}-\frac{3}{17.21}=\frac{2}{7}\)
=> \(x-\left(\frac{3}{1.5}+\frac{3}{5.9}+\frac{3}{9.13}+\frac{3}{13.17}+\frac{3}{17.21}\right)=\frac{2}{7}\)
=> \(x-\frac{3}{4}\left(\frac{4}{1.5}+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+\frac{4}{17.21}\right)=\frac{2}{7}\)
=> \(x-\frac{3}{4}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{3}-\frac{1}{17}+\frac{1}{17}-\frac{1}{21}\right)=\frac{2}{7}\)
=> \(x-\frac{3}{4}\left(1-\frac{1}{21}\right)=\frac{2}{7}\)
=> \(x-\frac{3}{4}.\frac{20}{21}=\frac{2}{7}\)
=> \(x-\frac{5}{7}=\frac{2}{7}\)
=> x = 1
Vậy x = 1
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115 + 3 . ( x - 2 ) = 295
3 . ( x - 2 ) = 295 - 115
3 . ( x - 2 ) = 180
x - 2 = 180 : 3
x - 2 = 60
x = 60 + 2
x = 62
16 : 2 . x = 9
x = ko tính được
20 - ( x +14 ) = 5
x + 14 = 20 - 5
x + 14 = 15
x = 15 - 14
x = 11
57 : ( 9 . x - 27 ) = 0
vì số nào chia 0 thì bằng 0 mà 27 : 9 = 3 nên
x = 3
Tìm x:
115+3.(x-2)= 295 16:2.x= 9 20-(x+14)=5 57:(9x-27)=0
3.(x-2)= 295-115 2.x= 16:9 x+14= 20-5 9x-27= 0
3.(x-2)= 180 2.x= 16/9. x+14= 15. 9x= 27
x-2= 180:3 x= \(\frac{16}{9}:2\) x= 15-14 x= 27:9
x-2= 60 \(x=\frac{16}{9}.\frac{1}{2}\) x= 1 x= 3
x= 60+2 \(x=\frac{8}{9}\)
x= 62
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1:
a: Vì \(\dfrac{-4}{3}=\dfrac{-4\cdot3}{3\cdot3}=\dfrac{-12}{9}=\dfrac{12}{9}\\ \Rightarrow\dfrac{-4}{3}=\dfrac{12}{9}\)
b: Vì : \(-2\cdot3=-6\\ -6\cdot8=-48\)
nên 2 p/s ko bằng nhau
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\(\frac{4^5\cdot9^42\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(=\frac{\left(2^2\right)^5\cdot\left(3^2\right)^4-2\cdot\left(2.3\right)^9}{2^{10}\cdot3^8+\left(2.3\right)^8\cdot2^2.5}\)
\(=\frac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}\)
\(=\frac{2^{10}\left(3^8-3^9\right)}{2^{10}\cdot\left(3^8+3^8\cdot5\right)}=\frac{2^{10}\cdot\left(-13122\right)}{2^{10}\cdot39366}=\frac{-13122}{39366}=-\frac{1}{3}\)
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x) \(\frac{-3}{7}.x-\left(\frac{1}{21}.x-\frac{-4}{9}\right)=\frac{2}{8}\)
\(\frac{-3}{7}.x-\frac{1}{21}.x-\frac{4}{9}=\frac{1}{4}\)
\(x.\left(\frac{-3}{7}-\frac{1}{21}\right)-\frac{4}{9}=\frac{1}{4}\)
\(x.\frac{\left(-10\right)}{21}-\frac{4}{9}=\frac{1}{4}\)
\(x.\frac{\left(-10\right)}{21}=\frac{1}{4}+\frac{4}{9}\)
\(x.\frac{\left(-10\right)}{21}=\frac{25}{36}\)
\(x=\frac{25}{36}:\left(\frac{-10}{21}\right)\)
\(x=\frac{-35}{24}\)
Chúc bn học tốt !!!
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\(\Rightarrow2S=6+\frac{3}{1}+\frac{3}{2}+...+\frac{3}{2^8}\)
\(\Rightarrow2S-S=\left(6+3+\frac{3}{2}+...+\frac{3}{2^8}\right)-\left(3+\frac{3}{2}+...+\frac{3}{2^9}\right)\)
\(\Rightarrow S=3-\frac{3}{2^9}\)
\(S=3+\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^9}\)
\(\Rightarrow\frac{1}{2}.S=\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{10}}\)
\(\Rightarrow S-\frac{1}{2}.S=\frac{1}{2}.S=3+\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^9}-\left(\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{10}}\right)\)
\(\Rightarrow\frac{1}{2}.S=3-\frac{3}{2^{10}}\)
\(\Rightarrow S=6-\frac{6}{2^{10}}\)