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a) -a -(b-a-c)
= -a -b+a+c
=(-a+a) +(c-b)
=c-b
b) -(a-c)-(a-b+c)
= -(a-c)-a+b-c
=-(a-c)-(a-c)+b
tự nghĩa nhe buồn ngủ rồi nhớ k đấy hứa rồi
a) -a - (b-a-c) = - a - b + a + c
= (a-a) + (c-b)
= c-b
b) -(a-c) - (a-b+c)
= - a + c - a + b - c
= -(a+a) + b + (c-c)
= - 2a + b
\(\frac{4}{3}B=-1+\frac{3}{4}-\left(\frac{3}{4}\right)^2+...+\left(\frac{3}{4}\right)^{99}\)
\(B=-\frac{3}{4}+\left(\frac{3}{4}\right)^2-\left(\frac{3}{4}\right)^3+...+\left(\frac{3}{4}\right)^{100}\)
\(\Rightarrow\)\(\frac{7}{3}B=-1+\left(\frac{3}{4}\right)^{100}\Rightarrow B=\frac{\left(\frac{3}{4}\right)^{100}-1}{\frac{7}{3}}=\frac{3\left[\left(\frac{3}{4}\right)^{100}-1\right]}{7}\)
Như vầy đủ gọn chưa bạn?
Tờ làm luôn, ko ghi đề nữa nhé
\(A=\frac{\frac{24}{12}-\frac{4}{12}+\frac{3}{12}}{\frac{24}{12}+\frac{2}{12}-\frac{3}{12}}\)
\(A=\frac{\frac{23}{12}}{\frac{23}{12}}=1\)
Vậy A=1
\(A=\frac{2-\frac{1}{3}+\frac{1}{4}}{2+\frac{1}{6}-\frac{1}{4}}\)\(=\frac{2-\frac{2}{6}+\frac{2}{8}}{2+\frac{2}{12}-\frac{2}{8}}\)\(=\frac{2\left(1-\frac{1}{6}+\frac{1}{8}\right)}{-2\left(1-\frac{1}{12}+\frac{1}{8}\right)}\)\(=-1\)
Bài 1:
a) 8154-(674+8154)+(-98+674)
=8154-674-8154-98+674
=-98
b) -25-21+25-72+49*25
=-21-72+1225
=1132
c) \(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\)
\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)
\(=\frac{1}{3}-\frac{1}{10}=\frac{7}{30}\)
Bài 2)
a) \(A=\left(-a+b-c\right)-\left(-a-b-c\right)\)
\(=-a+b-c+a+b+c=2b\)
b) \(B=\left(2a+b\right)-3b+\left(a-3c\right)-\left(3a+2c\right)\)
\(=2a+b-3b+a-3c-3a-2c=-2b-5c\)
1. Tính nhanh
a) 8154 - (674 + 8154) + (-98+674)
= 8154 - 674 - 8154 - 98 + 674
= (8154 - 8154) + (674 - 674) - 98
= 0 + 0 - 98
= -98
b) -25 - 21 + 25 - 72 + 49 . 25
= [(-25) + 25] - 21 - 72 + 49 . 25
= 0 - 21 - 72 + 49 . 25
= (-21 - 72) + (49 . 25)
= -93 + 1225
= 1132
c) \(\frac{1}{3.4}\) + \(\frac{1}{4.5}\) + \(\frac{1}{5.6}\) + \(\frac{1}{6.7}\) + \(\frac{1}{7.8}\) + \(\frac{1}{8.9}\) + \(\frac{1}{9.10}\)
= \(\frac{1}{3}-\frac{1}{4}\) + \(\frac{1}{4}-\frac{1}{5}\) + \(\frac{1}{5}-\frac{1}{6}\) + \(\frac{1}{6}-\frac{1}{7}\) + \(\frac{1}{7}-\frac{1}{8}\) + \(\frac{1}{8}-\frac{1}{9}\)+ \(\frac{1}{9}-\frac{1}{10}\)
= \(\frac{1}{3}-\frac{1}{10}\)
= \(\frac{7}{30}\)
2. Bỏ dấu ngoặc, thu gọn biểu thức
a) A = (-a + b - c) - (-a - b - c)
A = (-a) + b - c + a + b + c
A = (-a + a) + (b + b) + (c - c)
A = 0 + 2b + 0
A = 2b
b) B = (2a + b - 3b) + (a - 3c) - (3a + 2c)
B = 2a + b - 3b + a - 3c - 3a - 2c
B = (2a + a - 3a) + (b - 3b) + (-3c - 2c)
B = a(2 + 1 - 3) + b(1 - 3) + c(-3 - 2)
B = a0 + b . (-2) + c . (-5)
B = 0 + b . (-2) + c . (-5)
B = b . (-2) + c . (-5)
(a + b)(c + d) - (a + d)(b + c)
= a(c + d) + b(c + d) - [ a(b + c) + d(b + c)]
= ac + ad + bc + bd - [ ab + ac + bd + cd]
= ac + ad + bc + bd - ab - ac - bd - cd
= (ac - ac) + (bd - bd) + ad + bc - ab - cd
= ad + bc - ab - cd
= ad - ab - cd + bc
= a(d - b) - c(d - b)
= (a - c)(d - b) (ĐPCM)
M= (2a-b+c)-(a-b-3c)+(-a+b)
= 2a+b+c-a+b+3c-a+b
= 3b+4c
\(M=\left(2a-b+c\right)-\left(a-b-3c\right)+\left(-a-b\right)\)
\(M=2a-b+c-a+b+3c-a-b\)
\(M=-b+4c\)