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ta có
\(-\frac{80}{49}< -\frac{49}{49}=1=-\frac{73}{73}< -\frac{29}{73}\)
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\(a,\dfrac{11}{49}< \dfrac{11}{46};\dfrac{11}{46}< \dfrac{13}{46}\\ Nên:\dfrac{11}{49}< \dfrac{13}{46}\\ b,\dfrac{62}{85}< \dfrac{62}{80};\dfrac{62}{80}< \dfrac{73}{80}\\ Nên:\dfrac{62}{85}< \dfrac{73}{80}\\ c,\dfrac{n}{n+3}< \dfrac{n}{n+2};\dfrac{n}{n+2}< \dfrac{n+1}{n+2}\\ Nên:\dfrac{n}{n+3}< \dfrac{n+1}{n+2}\)
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a)13/57 và 29/73 MC(4161)
13/57 = 13.73/57.73 = 949/4161
29/73 = 29.57/73.57 = 1653/4161
949/4161 < 1653/4161 nên 13/57 < 29/73
b) 7/-12 và 11/-18 MC(36)
7/-12 = -7/12 = -7.3/12.3 = -21/36
11/-18 = -11/18 = -11.2/18.2 = -22/36
-21/36 > -22/36 nên 7/-12 > 11/-18
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a. Ta có \(\frac{-29}{39}=-1+\frac{10}{39}\)
\(\frac{-39}{49}=-1+\frac{10}{49}\)
có -1 = -1 mà \(\frac{10}{39}>\frac{10}{49}\)do cùng tử mà mẫu càng lớn thì phân số đó bé hơn
vì vậy nên \(\frac{-29}{39}>\frac{-39}{49}\)
b. có \(\frac{20142014:\text{10001}}{20152015:\text{10001}}=\frac{2014}{2015}\)
vậy \(\frac{20142014}{20152015}=\frac{2014}{2015}\)
Chúc bạn học tốt
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![](https://rs.olm.vn/images/avt/0.png?1311)
12/49 > 13/47
64/85 > 73/81
19/31 > 17/35
67/77 > 73/83
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Ta có A = \(\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}+\dfrac{1}{110}+\dfrac{1}{132}\)
= \(\dfrac{1}{6\cdot7}+\dfrac{1}{7\cdot8}+\dfrac{1}{8\cdot9}+\dfrac{1}{9\cdot10}+\dfrac{1}{10\cdot11}+\dfrac{1}{11\cdot12}\)
= \(\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{12}\)
= \(\dfrac{1}{6}-\dfrac{1}{12}=\dfrac{1}{12}\)
B = \(\dfrac{\dfrac{2}{29}-\dfrac{2}{39}+\dfrac{2}{49}}{\dfrac{23}{29}-\dfrac{23}{39}+\dfrac{23}{49}}=\dfrac{2\left(\dfrac{1}{29}-\dfrac{1}{39}+\dfrac{1}{49}\right)}{23\left(\dfrac{1}{29}-\dfrac{1}{39}+\dfrac{1}{49}\right)}=\dfrac{2}{23}\)
Lại có \(\dfrac{2}{23}>\dfrac{2}{24}=\dfrac{1}{12}\) hay A < B
Vậy A < B
Ta có: \(\frac{-29}{73}=\frac{-29\cdot49}{73\cdot49}=\frac{-1421}{3577}\)
\(\frac{-80}{49}=\frac{-80\cdot73}{49\cdot73}=\frac{-5840}{3577}\)
Vì \(\frac{-1421}{3577}>\frac{-5840}{3577}\) nên \(-\frac{29}{73}>\frac{-80}{49}\)
Cách 2:
Ta có: \(-\frac{29}{73}>-1\)
\(-\frac{80}{49}< -1\)
Do đó: \(-\frac{80}{49}< -1< \frac{-29}{73}\)
hay \(-\frac{80}{49}< \frac{-29}{73}\)