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![](https://rs.olm.vn/images/avt/0.png?1311)
a , ta có : 812 = ( 4 . 2 )12 = 424
128 = ( 4 . 3 ) 8 = 424
vì 24 = 24 nên 4^24 = 4^24
do đó 8^12 = 12^8 ..
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AI K MIK MIK K LẠI
a)\(12^8=\left(12^2\right)^4=144^4\)
\(8^{12}=\left(8^3\right)^4=512^4\)
\(144^4< 512^4\Rightarrow12^8< 8^{12}\)
b)\(\left(-5\right)^{39}=\left[\left(-5\right)^3\right]^{13}=\left(-125\right)^{13}\)
\(\left(-2\right)^{91}=\left[\left(-2\right)^7\right]^{13}=\left(-128\right)^{13}\)
\(\left(-125\right)^{13}>\left(-128\right)^{13}\Rightarrow\left(-5\right)^{39}>\left(-2\right)^{91}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 128 = 122.4 = (122)4 = 1444
812 = 83.4 = (83)4 = 5124
Vì 5124 > 1444
=> 812 > 128
b, (-5)39 = (-5)3.13 = [(-5)3]13 = (-125)13 = -12513
(-2)91 = (-2)7.13 = [(-2)7]13 = (-128)13 = -12813
Có 12513 < 12813
=> -12513 > -12813
=> (-5)39 > (-2)91
Có
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:128=(124)2=207362
812=(86)2=2621442
Vì 207362<2621442
Vậy 128< 812
b)Ta có:(-5)39=[(-5)3]13=(-125)13
(-2)91=[(-2)7]13=(-128)13
Vì (-128)13<(-125)13
Vậy (-2)91<(-5)39
Ta có: 128=(124)2=207362
812=(26)2=642
Vì 20736>64 nên 207362>642hay 128>812
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(12^8=\left(12^2\right)^4=144^4\)
\(8^{12}=\left(8^3\right)^4=512^4\)
Vì \(144^4< 512^4\Rightarrow12^8< 8^{12}\)
Vậy \(12^8< 8^{12}\)
b) \(\left(-5\right)^{39}=\left[\left(-5\right)^3\right]^{13}=\left(-125\right)^{13}\)
\(\left(-2\right)^{91}=\left[\left(-2\right)^7\right]^{13}=\left(-128\right)^{13}\)
Vì \(\left(-125\right)^{13}>\left(-128\right)^{13}\Rightarrow\left(-5\right)^{39}>\left(-2\right)^{91}\)
Vậy \(\left(-5\right)^{39}>\left(-2\right)^{91}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ Ta có :
\(12^8=\left(12^2\right)^4=144^4\)
\(8^{12}=\left(8^3\right)^4=512^4\)
Vì \(144^4< 512^4\Leftrightarrow12^8< 8^{12}\)
b/ Ta có :
\(\left(-5\right)^{39}=\left[\left(-5\right)^3\right]^{13}=\left(-125\right)^{13}\)
\(\left(-2\right)^{91}=\left[\left(-2\right)^7\right]^{13}=\left(-128\right)^{13}\)
Vì \(\left(-125\right)^{13}< \left(-128\right)^{13}\Leftrightarrow\left(-5\right)^{39}< \left(-2\right)^{91}\)
sai rùi bn ạ -125>-128 nên suy ra
(-125)mũ 13 >-128 mũ 13 chứ
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ Ta có :
\(12^8=\left(12^2\right)^4=24^4\)
\(8^{12}=\left(8^3\right)^4=512^4\)
Vì \(24^4< 512^4\Leftrightarrow12^8< 8^{12}\)
b/ \(\left(-5\right)^{39}=\left[\left(-5\right)^3\right]^{13}=\left(-125\right)^{13}\)
\(\left(-2\right)^{91}=\left[\left(-2\right)^7\right]^{13}=\left(-128\right)^{13}\)
Vì \(\left(-125\right)^{13}>\left(-128\right)^{13}\Leftrightarrow\left(-5\right)^{39}>\left(-2\right)^{91}\)
a)Ta có :
\(12^8=12^{2.4}=\left(12^2\right)^4=144^4\)
\(8^{12}=8^{3.4}=\left(8^3\right)^4=512^4\)
Mà 512>144 nên \(512^4>144^4\)
Vậy \(8^{12}>12^8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có:
128 = (122)4 = 1444
812 = (83)4 = 5124
Vì 1444 < 5124
=> 128 < 812
b) (-5)39 = -539 =-(53)13 = -12513
(-2)91 = -291 = -(27)13 = -12813
Vì -12513 > -12813
=> (-5)39 > (-2)91
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ Ta có :
\(12^8=\left(12^2\right)^4=24^4\)
\(8^{12}=\left(8^3\right)^4=512^4\)
Vì \(24^4< 512^4\Leftrightarrow12^8< 8^{12}\)
b/ Ta có :
\(\left(-5\right)^{39}=\left[\left(-5\right)^3\right]^{13}=\left(-125\right)^{13}\)
\(\left(-2\right)^{91}=\left[\left(-2\right)^7\right]^{13}=\left(-128\right)^{13}\)
Vì \(\left(-125\right)^{13}>\left(-128\right)^{13}\Leftrightarrow\left(-5\right)^{39}>\left(-2\right)^{91}\)
a)Ta có:128=(122)4=1444
812=(83)4=5124
Vì 1444<5124
Suy ra:128<812
b)Ta có:(-5)39=[(-5)3]13=(-125)13
(-2)91=[(-2)7]13=(-128)13
Vì (-128)13<(-125)13
Suy ra:(-2)91<(-5)39
\(a.\) \(12^8\) và \(8^{12}\)
Ta có :
\(12^8=\left(12^2\right)^4=114^4\)
\(8^{12}=\left(8^3\right)^4=512^4\)
Vì \(114^4< 512^4\) nên \(12^8< 8^{12}\)
Vậy : \(12^8< 8^{12}\)
\(b.\) \(\left(-5\right)^{39}\) và \(\left(-2\right)^{91}\)
Ta có :
\(\left(-5\right)^{39}=\left(-5^3\right)^{13}=\left(-125\right)^{13}\)
\(\left(-2\right)^{91}=\left(-2^7\right)^{13}=\left(-128\right)^{13}\)
Vì \(\left(-125\right)^{13}>\left(-128\right)^{13}\) nên \(\left(-5\right)^{39}>\left(-2\right)^{91}\)