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a: -3/4=-9/12
-5/6=-10/12
mà -9>-10
nên -3/4>-5/6
b: -5/17<0<2/7
c: 11/10>1>9/14
![](https://rs.olm.vn/images/avt/0.png?1311)
1, A = 291 = 27.13 = (213)7 = 81927
B = 535 = 55.7 = (55)7 = 31257
Vì 3125 < 8192
=> 31257 < 81927
=> B < A
2.Ta có:
A=11+112+113+114+...+11199+11200.
11A=112+113+114+...+11199+11200+11201.
11A-A=11201-11.
10A=11201-11.
A=(11201-11):10
Quan sát 2 vế A và B thì ta thấy rõ ràng vế A<B hay B>A.
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
a) \(-\frac{15}{17}>-\frac{19}{21}\)
b)\(-\frac{13}{19}>-\frac{19}{23}\)
c)\(-\frac{23}{49}>-\frac{25}{47}\)
d)\(\frac{317}{633}>\frac{371}{743}\)
e)\(-\frac{24}{35}< -\frac{19}{30}\)
f)\(\frac{12}{17}< \frac{13}{18}\)
g) \(-\frac{17}{26}< -\frac{16}{27}\)
h) \(\frac{84}{-83}< -\frac{337}{331}\)
i) \(-\frac{1941}{1931}< -\frac{2011}{2001}\)
j) \(-\frac{1930}{1945}>-\frac{1996}{2001}\)
k) \(\frac{37}{59}< \frac{47}{59}\)
I) \(-\frac{25}{124}>-\frac{27}{100}\)
m) \(-\frac{97}{201}>-\frac{194}{309}\)
n) \(-\frac{189}{398}< -\frac{187}{394}\)
o) \(-\frac{289}{403}>-\frac{298}{401}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 11/9 > 0
-17/36 < 0
⇒ 11/9 > -17/36
b) -13/4 < -12/4 (= -3)
-11/5 > -15/5 (= -3)
⇒ -13/4 < -11/5
c) Do 5,510 < 5,580
⇒ -5,510 > -5,580
d) -171,3 < 0
0,25 > 0
⇒ -171,3 < 0,25
a) 11/9 > 0
-17/36 < 0
⇒ 11/9 > -17/36
b) -13/4 < -12/4 (= -3)
-11/5 > -15/5 (= -3)
⇒ -13/4 < -11/5
c) Do 5,510 < 5,580
-> -5,510 > -5,580
d) -171,3 < 0
0,25 > 0
-> -171,3 < 0,25
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\left(-\frac{1}{2013}-\frac{3}{11^2}-\frac{5}{11^3}-\frac{3}{11^4}\right)-\frac{4}{11^4};B=\left(-\frac{1}{2013}-\frac{3}{11^2}-\frac{5}{11^3}-\frac{3}{11^2}\right)-\frac{4}{11^2}\)
Vì 114 > 112 nên \(\frac{4}{11^4}-\frac{4}{11^2}\) => A > B
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\dfrac{-7}{6}=\dfrac{-7\cdot3}{6\cdot3}=\dfrac{-21}{18}\)
\(\dfrac{-11}{9}=\dfrac{-11\cdot2}{9\cdot2}=\dfrac{-22}{18}\)
mà -21>-22
nên \(-\dfrac{7}{6}>-\dfrac{11}{9}\)
b: \(\dfrac{5}{-7}=\dfrac{-5}{7}=\dfrac{-5\cdot5}{7\cdot5}=\dfrac{-25}{35}\)
\(\dfrac{-4}{5}=\dfrac{-4\cdot7}{5\cdot7}=\dfrac{-28}{35}\)
mà -25>-28
nên \(\dfrac{5}{-7}>\dfrac{-4}{5}\)
c: \(\dfrac{-8}{7}< -1\)
\(-1< -\dfrac{2}{5}\)
Do đó: \(-\dfrac{8}{7}< -\dfrac{2}{5}\)
d: \(-\dfrac{2}{5}< 0\)
\(0< \dfrac{1}{3}\)
Do đó: \(-\dfrac{2}{5}< \dfrac{1}{3}\)