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a/
\(A=999^8\left(999+1\right)=1000.999^8\)
\(B=1000.1000^8\)
=> B>A
b/
\(2A=2+2^2+2^3+...+2^{10}+2^{11}\)
\(2A=1+2+2^2+2^3+...+2^{10}+2^{11}-1\)
\(2A=A+2^{11}-1\)
\(A=2^{11}-1\)
\(B=2^{11}-2\)
=> A>B
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=999^9+999^8=999^8\left(999+1\right)=999^8.1000< 1000^8.1000=1000^9\)
Trả lời :..............................
a < b........................
Hk tốt
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a < b
vì a = 9,920279441x10^26
b = 1x10^27
chuyển 500000 đ để mua máy tính mới nha
![](https://rs.olm.vn/images/avt/0.png?1311)
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Câu 1:
\(3^{2x-1}=27\)
\(\Leftrightarrow3^{2x-1}=3^3\)
\(\Leftrightarrow2x-1=3\)
\(\Leftrightarrow2x=4\)
\(\Leftrightarrow x=2\)
Câu 2:
Ta có: \(1000^9=999.1000^8+1000^8\)
Vì: \(999.1000^8>999.999^8=999^9\)và \(1000^8>999^8\)
\(\Rightarrow1000^9>999^9+999^8\)
Hay: \(B>A\)
\(C1:\)
\(3^{2x-1}=27\)
\(3^{2x-1}=3^3\)
\(\Rightarrow2x-1=3\)
\(2x=4\)
\(x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)