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L
2
19 tháng 12 2021
^$@*&^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%$%$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$%%%%%%%%$%%$%$%$%$%%%%%%%%%%%%%%%%%%454%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%$%%%%%%%%%%%%$%$%%$$%$%$%$%$%$%$%$%$
15 tháng 8 2015
\(A=\frac{3}{8^3}+\frac{7}{8^4}=\frac{3}{8^3}+\frac{3}{8^4}+\frac{4}{8^4}\)
\(B=\frac{7}{8^3}+\frac{3}{8^4}=\frac{3}{8^3}+\frac{3}{8^4}+\frac{4}{8^4}\)
\(A=\frac{3}{8^3}+\frac{3}{8^4}+\frac{4}{8^3}>B=\frac{3}{8^3}+\frac{3}{8^4}+\frac{4}{8^4}\)
vậy A>B
HM
5
26 tháng 6 2023
`@` `\text {Ans}`
`\downarrow`
`1,`
`a)`
`3^12` và `5^8`
\(3^{12}=\left(3^3\right)^4=9^4\)
\(5^8=\left(5^2\right)^4=25^4\)
Vì `9 < 25` `=> 25^4 > 9^4`
`=> 3^12 > 5^8`
Vậy, `3^12 > 5^8`
`b)`
`(0,6)^9` và `(-0,9)^6`
\(\left(0,6\right)^9=\left(0,6^3\right)^3=\left(0,216\right)^3\)
\(\left(-0,9\right)^6=\left[\left(-0,9\right)^2\right]^3=\left(0,81\right)^3\)
Vì `0,81 > 0,216 => (0,81)^3 > (0,216)^3`
`=> (0,6)^9 < (-0,9)^6`
Vậy, `(0,6)^9<(-0,9)^6`
XO
26 tháng 6 2023
1.a) Có 312 = 33.4 = 274 ;
58 = 52.4 = 254
Dễ thấy 274 > 254 nên 312 > 58
b) Có \(0,6^9=\dfrac{6^9}{10^9}=\dfrac{6^{3.3}}{10^9}=\dfrac{216^3}{10^9}\)
mà \(\left(-0,9\right)^6=0,9^6=\dfrac{9^6}{10^6}=\dfrac{9^6.10^3}{10^9}=\dfrac{9^{2.3}.10^3}{10^9}=\dfrac{81^3.10^3}{10^9}=\dfrac{810^3}{10^9}\)
Dễ thấy \(\dfrac{216^3}{10^9}< \dfrac{810^3}{10^9}\Rightarrow0,6^9< \left(-0,9\right)^6\)
NT
1
10 tháng 1 2017
Ta có :
19 < 89
29 < 89
.......
89 = 89
=> 19 + 29 + .... + 89 < 89 + 89 + .... + 89 = 8.89 = 810 < 910 ( số trung gian là 810 )
=> 19 + 29 + .... + 89 < 910
L
20 tháng 8 2019
a, \(4^{100}=\left(2^2\right)^{100}=2^{200}< 2^{202}\)
\(\Rightarrow\text{ }4^{100}< 2^{202}\)
b, \(3^0=1< 5^8\)
\(3^0< 5^8\)
c, \(\left(0,6\right)^0=1\)
\(\left(-0,9\right)^6=\left(0,9\right)^6\)
\(\Rightarrow\text{ }\left(0,6\right)^0< \left(-0,9\right)^6\)
d,
e, \(8^{12}=\left(2^3\right)^{12}=2^{36}=2^{16}\cdot2^{20}=2^{16}\cdot\left(2^4\right)^5=2^{16}\cdot16^5\)
\(12^8=\left(2^2\cdot3\right)^8=2^{16}\cdot3^8=2^{16}\cdot\left(3^2\right)^4=2^{16}\cdot9^4\)
Vì \(2^{16}\cdot16^5>2^{16}\cdot9^4\text{ }\Rightarrow\text{ }8^{12}>12^8\)
NT
1
7 tháng 6 2018
1. -2/3 < 0
2. 0,125 > -1/8
3. 3/7 < 11/15
4 -11/6 < -8/9
5 297/16 . 306/25
6 -265/317 < 83/111
chúc bạn học tốt
8⁵ = (2³)⁵ = 2¹⁵ = 2.2¹⁴
3.4⁷ = 3.(2²)⁷ = 3.2¹⁴
Do 2 < 3 nên 2.2¹⁴ < 3.2¹⁴
Vậy 8⁵ < 3.4⁷
\(8^5=2^{15}=2.2^{14}\)
\(3.4^7=3.2^{14}>2.2^{14}\)
\(\Rightarrow8^5< 3.4^7\)