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a.156*75+25*150
=156*25*3+25*150
=25*(156*3+150)
=25*618
=15450
b,791*101-791
=791*101-791*1
=791*(101-1)
=791*100
=79100
c,2*15*4*25
=(2*15)*(4*25)
=30*100
=3000
![](https://rs.olm.vn/images/avt/0.png?1311)
a. Thay a = 14, b = 15, c = 10, ta có:
\(a=a\times b+200\)
\(=>a=14\times15+200\)
\(=>a=210+200=410\)
___
\(b=a\times b\times c\)
\(=>b=14\times15\times10=2100\)
b. Vì 410 < 2100 nên a < b.
\(#NqHahh\)
a: Khi a=14 và b=15 thì \(A=14\cdot15+200=210+200=410\)
Khi a=14 và b=15 và c=10 thì \(B=14\cdot15\cdot10=210\cdot10=2100\)
b: A=410
B=2100
=>A<B
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a ) y : 102 = 203 ( dư 101 )
y=203x102+101
y=20 706+101
y=20 807
b ) 25 x y x 4 = 500
25xy=500:4
25xy=125
y=125:25
y=5
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`a)25xx532xx4`
`=(25xx4)xx432`
`=432xx100=43200`
`b)456xx200-456xx100`
`=456xx(200-100)`
`=456xx100=45600`
\(a,25\times432\times4=25\times4\times432=100\times432=4320\\ b,456\times200-456\times100=456\times\left(200-100\right)=456\times100=45600\)
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Ta có :
A = 101 x 50
B = 50 x 49 + 53 x 50
= 50 x ( 49 + 53 )
= 50 x 102
Vì 101 x 50 < 50 x 102
=> A < B
Vậy : A < B
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\(\frac{29}{60}< \frac{4}{9}\)
\(\frac{6}{28}< \frac{101}{400}\)
\(\frac{131313}{393939}=\frac{1}{3}\)
a) ta có: \(\frac{29}{60}=0,483;\frac{4}{9}=0,44\)
\(\Rightarrow0,483>0,44\Rightarrow\frac{29}{60}>\frac{4}{9}\)
b) ta có: \(\frac{6}{28}=\frac{3}{14}=0,21;\frac{101}{400}=0,25\)
\(\Rightarrow0,21< 0,25\Rightarrow\frac{6}{28}< \frac{101}{400}\)
c) ta có: \(\frac{131313}{393939}=\frac{13x10101}{39x10101}=\frac{13}{39}=\frac{1}{3}\)
\(\Rightarrow\frac{131313}{393939}=\frac{1}{3}\)
Đáp án B