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ᵃ, ᵗᵃ ʳᵘ́ᵗ ᵍᵒ̣ⁿ :\(\dfrac{18}{24}=\dfrac{3}{4}\) ;
ᵗᵃ ʳᵘ́ᵗ ᵍᵒ̣ⁿ :\(\dfrac{15}{25}=\dfrac{3}{5}\)
Vì \(\dfrac{3}{4}>\dfrac{3}{5}\\ \Rightarrow\dfrac{18}{24}>\dfrac{15}{25}\)
ᵇ, ᵗᵃ ʳᵘ́ᵗ ᵍᵒ̣ⁿ :\(\dfrac{21}{15}=\dfrac{7}{5}\\ \dfrac{28}{24}=\dfrac{7}{6}\)
Vì \(\dfrac{7}{5}>\dfrac{7}{6}\\ \Rightarrow\dfrac{21}{15}>\dfrac{28}{24}\)
a, \(\dfrac{18}{24}\) = \(\dfrac{3}{4}\) \(\dfrac{15}{25}\) = \(\dfrac{3}{5}\)
\(\dfrac{3}{4}\) > \(\dfrac{3}{5}\) vậy \(\dfrac{18}{24}\) > \(\dfrac{15}{25}\)
b, \(\dfrac{21}{15}\) = \(\dfrac{7}{5}\) \(\dfrac{28}{24}\) = \(\dfrac{7}{6}\)
\(\dfrac{7}{5}\) > \(\dfrac{7}{6}\) vậy \(\dfrac{21}{15}\) > \(\dfrac{28}{24}\)
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\(\frac{16}{48}=\frac{16:16}{48:16}=\frac{1}{3}\);\(\frac{14}{35}=\frac{14:7}{35:7}=\frac{2}{5}\)
\(\frac{1}{3}=\frac{1\cdot5}{3\cdot5}=\frac{5}{15}\); \(\frac{2}{5}=\frac{2\cdot3}{5\cdot3}=\frac{6}{15}\)
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\(\dfrac{5}{7}\)>\(\dfrac{6}{21}\)
\(\dfrac{18}{24}\)>\(\dfrac{15}{25}\)
\(\dfrac{12}{13}\)=\(\dfrac{1212}{1313}\)
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a) \(\dfrac{6}{14}=\dfrac{6:2}{14:2}=\dfrac{3}{7}\)
\(\dfrac{3}{7}< \dfrac{4}{7}\)
b) \(\dfrac{6}{15}=\dfrac{6:3}{15:3}=\dfrac{2}{5}\)
\(\dfrac{3}{5}>\dfrac{2}{5}\)
c) \(\dfrac{10}{18}=\dfrac{10:2}{18:2}=\dfrac{5}{9}\)
\(\dfrac{5}{9}>\dfrac{2}{9}\)
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Cách 1 :
Rút gọn : 12/16 = 3/4 , 28/21 = 4/3
So sánh : 12/16 < 28/21
Cách 2 :
So sánh Vì 12/16 < 1 và 28/ 21 > 1 nên 28/21 > 12/16
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\(\dfrac{5}{7}=\dfrac{5\times3}{7\times3}=\dfrac{15}{21}\)
Vì \(\dfrac{15}{21}< \dfrac{17}{21}\Rightarrow\dfrac{5}{7}< \dfrac{17}{21}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{90}{126}=\dfrac{5}{7}\)
\(\Rightarrow\dfrac{90}{126}< \dfrac{6}{7}\) (Vì \(\dfrac{5}{7}< \dfrac{6}{7}\))
\(\dfrac{35}{49}=\dfrac{5}{7}\)
\(\Rightarrow\dfrac{90}{126}=\dfrac{35}{49}\) (Vì \(\dfrac{5}{7}=\dfrac{5}{7}\))
a.Ta có:
\(\dfrac{14}{18}=\dfrac{7}{9}=\dfrac{7\times5}{9\times5}=\dfrac{35}{45}\)
\(\dfrac{21}{35}=\dfrac{3}{5}=\dfrac{3\times9}{5\times9}=\dfrac{27}{45}\)
\(\Rightarrow\dfrac{14}{18}>\dfrac{21}{35}\)
14/8 = 35/45 , 21/35 = 27/45
nên 14/18>21/35
(HT)