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23 tháng 3 2021
a) \(\dfrac{11\cdot8-11\cdot3}{17-6}\)
\(=\dfrac{11\cdot\left(8-3\right)}{11}=5\)
b) \(\dfrac{24-12\cdot13}{12+4\cdot9}\)
\(=\dfrac{12\cdot\left(2-13\right)}{12\left(1+3\right)}=\dfrac{-11}{4}\)
9 tháng 2 2022
a \(\dfrac{-2}{5}\)
b -1
c \(\dfrac{2}{5}\)
d \(\dfrac{-18}{11}\)
8 tháng 3 2022
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13 tháng 1 2022
Bài 1:
a: =-3/7
b: =-3/5
c: =1/13
d: =-1/2
Bài 2:
a: \(=\dfrac{21\cdot11}{22\cdot9}=\dfrac{1}{2}\cdot\dfrac{7}{3}=\dfrac{7}{6}\)
b: \(=\dfrac{49\cdot8}{10}=\dfrac{196}{5}\)
H
20 tháng 8 2023
d)
\(\dfrac{3^9.3^{20}.2^8}{3^{24}.243.2^6}\\ =\dfrac{3^{29}.2^6.2^2}{3^{24}.3^5.2^6}\\ =\dfrac{3^{29}.2^6.4}{3^{29}.2^6}\\ =4\)
e)
\(\dfrac{2^{15}.5^3.2^6.3^4}{8.2^{18}.81.5}\\ =\dfrac{2^{21}.5^3.3^4}{2^3.2^{18}3^4.5}\\ =\dfrac{2^{21}.5.5^2.3^4}{2^{21}.3^4.5}\\ =5^2\\ =25\)
f)
\(=\dfrac{24\left(315+561+124\right)}{\dfrac{\left(1+99\right).50}{2}-500}\\ =\dfrac{24.1000}{2500-500}\\ =12\)
T
20 tháng 8 2023
\(a,\dfrac{-14.15}{21.\left(-10\right)}=\dfrac{-7.2.3.5}{7.3.\left(-2\right).5}=1\)
\(b,\dfrac{5.7-7.9}{7.2+6.7}=\dfrac{7\left(5-9\right)}{7\left(2+6\right)}=\dfrac{-4}{8}=-\dfrac{1}{2}\)
\(c,\dfrac{\left(-7\right).3+2.\left(-14\right)}{\left(-5\right).7-2.7}=\dfrac{-7.\left(3+4\right)}{7\left(-5-2\right)}\)
\(=\dfrac{\left(-7\right).7}{7.\left(-7\right)}=1\)
\(d,\dfrac{3^9.3^{20}.2^8}{3^{24}.243.2^6}=\dfrac{3^{29}.2^8}{3^{24}.3^5.2^6}=\dfrac{3^{29}.2^8}{3^{29}.2^6}=2^2=4\)
\(e,\dfrac{2^{15}.5^3.2^6.3^4}{8.2^{18}.81.5}=\dfrac{2^{21}.3^4.5^3}{2^{18}.2^3.3^4.5}=\dfrac{2^{21}.3^4.5^3}{2^{21}.3^4.5}=5^2=25\)
\(f,\dfrac{24.315+3.561.8+4.124.6}{1+3+5+...+97+99-500}\)
\(=\dfrac{24.315+24.561+24.124}{1+3+5+...+97+99-500}\)
\(=\dfrac{24\left(315+561+124\right)}{1+3+5+...+97+99-500}\)
\(=\dfrac{24.1000}{1+3+5+...+97+99-500}\) (1)
Đặt A = 1 + 3 + 5 + ... + 97 + 99
Số số hạng trong A là: (99 - 1) : 2 + 1 = 50 (số)
Tổng A bằng: (99 + 1) . 50 : 2 = 2500
Thay A = 2500 vào biểu thức (1), ta được:
\(\dfrac{24.1000}{2500-500}=\dfrac{24.1000}{2.1000}=12\)
CM
28 tháng 12 2019
a) − 7 .3 + 4. − 6 − 5 .3 + 2.3 = − 45 = 9 = 6
b) 3.6 + 2.9.5 − 18. − 4 7. − 7 + 12. − 7 + 7 = 18. 1 + 5 + 4 − 7 . 7 + 12 − 1 = 18.10 − 7.18 = − 10 7
5 tháng 2 2023
`a) ((-14).15)/(21.(-10))`
`=(-7.3.5.3)/(7.3.(-2).5)`
`=3/2`
`b) ((-7).12)/((-16).(-14))`
`=(-7.3.2.2)/(-2.2.2.(-7).2)`
`=(-3)/4`
`c) ((-11).(-5))/(15.22) `
`=(-11.(-5))/(3.5.11.2)`
`=1/6`
`d) ((-10).(-18))/((-6).25.7)`
`=(-5.2.-2.3.3)/(-2.3.5.5.7)`
`=6/35`
`e) (5.7-7.9)/(7.2+6.7)`
`=(7.(5-9))/(7.(2+6))`
`=-4/8`
`=-1/2`
`f) (11.9-22.3)/(33.2)`
`=(33.(3-2))/(33.2)`
`=1/2`
mik cần gấp ak
a) \(\frac{3\cdot5\cdot7}{14\cdot55}=\frac{3\cdot5\cdot7}{2\cdot7\cdot11\cdot5}=\frac{3}{2\cdot11}=\frac{3}{22}\)
b) \(\frac{2^7\cdot3^4}{3^6\cdot2^5}=\frac{2^2\cdot2^5\cdot3^4}{3^2\cdot3^4\cdot2^5}=\frac{2^2}{3^2}=\frac{4}{9}\)
c) \(\frac{7\cdot9-7\cdot4}{14\cdot11-14}=\frac{7\left(9-4\right)}{14\cdot\left(11-1\right)}=\frac{7\cdot5}{14\cdot10}=\frac{7\cdot5}{2\cdot7\cdot2\cdot5}=\frac{1}{2\cdot2}=\frac{1}{4}\)