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\(\frac{3^6.\left(3^2.5\right)^4-\left(3.5\right)^3:5^9}{\left(3^3\right)^4.\left(5^2\right)^3+\left(5.3^2\right)^6}\) = \(\frac{3^{14}.5^4-3^3:5^6}{3^{12}.5^6+5^6.3^{12}}\) = \(\frac{3^{14}.5^{10}-3^3}{3^{12}.5^{12}+5^{12}.3^{ }^{12}^{ }}=\frac{3^{11}.5^{10}-1}{2.3^9.5^{12}}\)
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\(E=\frac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}\)
\(E=\frac{3^6.3^8.5^4-3^{13}.5^{13}.5^{-9}}{3^{12}.5^6+3^{12}.5^6}\)
\(E=\frac{3^{14}.5^4-3^{13}.5^4}{3^{12}.5^6\left(1+1\right)}\)
\(E=\frac{3^{13}.5^4\left(3-1\right)}{3^{12}.5^6.2}\)
\(E=\frac{3}{25}\)
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Tính:
\(\dfrac{3^6.45^4-15^{13}.\dfrac{1}{5^9}}{27^4.25^3+45^6}\)
\(=\dfrac{3^6.\left(3^2.5\right)^4-\left(3.5\right)^{13}.5^{-9}}{\left(3^3\right)^4.\left(5^2\right)^3+\left(3^2.5\right)^6}\)
\(=\dfrac{3^6.3^8.5^4-3^{13}.5^{13}.5^{-9}}{3^{12}.5^6+3^{12}.5^6}\)
\(=\dfrac{3^{14}.5^4-3^{13}.5^4}{3^{12}.5^6+3^{12}.5^6}\)
\(=\dfrac{3^{13}.5^4.\left(3-1\right)}{2.3^{12}.5^6}\)
\(=\dfrac{3.2}{2.5^2}\)
\(=\dfrac{3}{25}.\)
Đoàn Đức Hiếu, Nguyễn Thanh Hằng, Nguyễn Huy Tú, Tuấn Anh Phan Nguyễn, Hoàng Ngọc Anh, ...
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\(=\frac{3^6.9^4.5^4-3^{13}.5^{13}.5^9}{3^{12}.5^6+9^4.5^4}=\frac{3^6.3^8.5^4-3^{12}.5^{22}}{3^{12}.5^6+3^8.5^4}=\frac{5^4.3^{12}\left(3^{12}-5^{18}\right)}{5^4.3^8\left(3^4.5+1\right)}=\frac{3^4.\left(3^{12}-5^{18}\right)}{3^4.5+1}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
d = \(\frac{2^{10}.13+2^{10}.65}{2^8.65}\)
\(\Rightarrow\frac{2^{10}\left(13+65\right)}{2^8.65}\)
\(\Rightarrow\frac{2^{10}.78}{2^8.65}\Rightarrow\frac{2^2.78}{65}\Rightarrow\frac{24}{5}\)