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a) (3x2 – 2x2y) : x2 – (2xy2 + x2y) : (1/3 xy)
= (3x3 : x2) + (-2x2y : x2) - [(2x2y : 1/3 xy) +( x2y : 1/3 xy)]
= 3x – 2y – (6y + 3x) = 3x – 2y – 6y – 3x = -8y
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c: \(\dfrac{1}{8}x^3-\dfrac{9}{4}x^2y+\dfrac{27}{2}xy^2-27y^3=\left(\dfrac{1}{2}x-3y\right)^3\)
b: \(-x^3+12x^2-48x+64=\left(-x+4\right)^3\)
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M = x 3 + y 3 + z 3 - 3 x y z x 2 + y 2 + z 2 - x y - y z - x z
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Bài 1:
\(a,6x^2-15x^3y\\ b,=-\dfrac{2}{3}x^2y^3+\dfrac{2}{3}x^4y-\dfrac{8}{3}xy\)
Bài 2:
\(a,=20x^3-10x^2+5x-20x^3+10x^2+4x=9x\\ b,=3x^2-6x-5x+5x^2-8x^2+24=24-11x\\ c,=x^5+x^3-2x^3-2x=x^5-x^3-2x\)
\(2x^2y-x^3-xy+1+x^3+2xy^2-2\)
\(=\left(-x^3+x^3\right)+\left(1-2\right)+2x^2y-xy+2xy^2\)
\(=0-1+2x^2y-xy+2xy^2\)
\(=2x^2y-xy+2xy^2-1\)