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Bài làm
\(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}\)
\(=\frac{2^{10}\left(3^{10}-3^9\right)}{2^9.3^{10}}\)
\(=\frac{2\left[3^9\left(3-1\right)\right]}{3^{10}}\)
\(=\frac{2\left[3^9.2\right]}{3^{10}}\)
\(=\frac{4.3^9}{3^{10}}\)
\(=\frac{4}{3}\)
Vậy giá tị biểu thức là \(\frac{4}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Hai câu a) và b) bạn chỉ cần xem số mũ rồi trừ số mũ là xong
\(c)\) \(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.3^9\left(3-1\right)}{2^9.3^{10}}=\frac{2^{10}.3^9.2}{2^9.3^{10}}=\frac{2^{11}.3^9}{2^9.3^{10}}=\frac{2^2}{3}=\frac{4}{3}\)
\(d)\) \(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.7^{11}\left(7+1\right)}{5^{11}.7^{11}\left(5.7+9\right)}=\frac{8}{35+9}=\frac{8}{44}=\frac{2}{11}\)
Chúc bạn học tốt
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nhìu thế
đăng từng câu một mới có cơ có người trả lời đó bạn
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\(\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}\)\(=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}\)\(=\frac{2\cdot2}{3}=\frac{4}{3}\)
Vậy \(\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{3}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a. \(\dfrac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}\) = \(\dfrac{3^{10}.\left(-5\right)^{20}.\left(-5\right)}{\left(-5\right)^{20}.3^{10}.3^2}\) = \(\dfrac{-5}{3^2}\)= \(\dfrac{-5}{9}\)
b. \(\dfrac{-11^5.13^7}{11^5.13^8}\) = \(\dfrac{-11^5.13^7}{11^5.13^7.13}\)= \(\dfrac{-1}{13}\)
c. \(\dfrac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}\)= \(\dfrac{2^{10}\left(3^{10}-3^9\right)}{2^9.3^{10}}\)= \(\dfrac{2^{10}.3}{2^9.3^{10}}\)= \(\dfrac{2^9.2.3}{2^9.3.3^9}\)= \(\dfrac{2}{3^9}\)=\(\dfrac{2}{19683}\)
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a ) Tử số : 2^10 . 3^10 - 2^10 . 3^9
= 2^10 . 3^9 ( 3 - 1 )
= 2^10 . 3^9 . 2 = 2^11 . 3^9
=> Phân số : 2^11 . 3^9 /2^9 . 3^10 = 4/3
b ) 5^12 . 7^12 + 9 . 5^11 . 7^11
= 5^11 . 7^11 ( 5 . 7 + 9 )
=5^11 . 7^11 . 44
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(-\right)\frac{1989\cdot1990+3970}{1992\cdot1991+3984}=\frac{1989\cdot\left(1990+2\right)}{1992\cdot\left(1991+2\right)}=\frac{1989}{1993}\)
\(\left(-\right)\frac{3^{10}\cdot\left(-5\right)^{21}}{\left(-5\right)^{20}\cdot3^{12}}=\frac{3^{10}\cdot\left(-5\right)^{20}\cdot\left(-5\right)}{3^{10}\cdot\left(-5\right)^{20}\cdot3^2}=-\frac{5}{9}\)
\(\left(-\right)\frac{\left(-11\right)^5\cdot13^7}{11^5\cdot13^8}=\frac{11^5\cdot13^7\cdot\left(-1\right)}{11^5\cdot13^7\cdot13}=-\frac{1}{13}\)
\(\left(-\right)\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}=\frac{2^{11}\cdot3^9}{2^9\cdot3^{10}}=\frac{4}{3}\)
\(\frac{-11^5.13^7}{11^5.13^8}=\frac{\left(-1\right).11^5.13^7}{11^5.13^7.13}=\frac{-1}{13}\)
\(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.\left(3^{10}-3^9\right)}{2^9.3^{10}}=\frac{2^9.2.3^9.\left(3-1\right)}{2^9.3.3^9}=\frac{2.2}{3}=\frac{4}{3}\)
a, \(\frac{-11^5.13^7}{11^5.13^8}=\frac{-1}{13}\)
b, \(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.3^9.\left(1-3\right)}{2^9.3^{10}}=\frac{-4}{3}\)