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\(8+8\left(x-2\right)^3\)
\(=8\left[1+\left(x-2\right)^3\right]\)
\(=8\left(1+x-2\right)\left[1-\left(x-2\right)+\left(x-2\right)^2\right]\)
\(=8\left(x-1\right)\left(1-x+2+x^2-4x+4\right)\)
\(=8\left(x-1\right)\left(x^2-5x+7\right)\)
#\(Toru\)
=8[(x-2)^3+1]
=8(x-2+1)[(x-2)^2-(x-2)+1]
=8(x-1)(x^2-4x+4-x+2+1)
=8(x-1)(x^2-5x+7)
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x 3 – 6 x 2 y + 12 x y 2 – 8 y 3 = x 3 – 3 . x 2 . ( 2 y ) + 3 . x . ( 2 y ) 2 – ( 2 y ) 3 = ( x – 2 y ) 3
đáp án cần chọn là: D
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Ta có
x 3 8 + 8 y 3 = x 2 3 + 2 y 3 = x 2 + 2 y x 2 2 - x 2 . 2 y + 2 y 2 = x 2 + 2 y x 2 4 - x y + 4 y 2
Đáp án cần chọn là: B
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b) \(\left(a^2+b^2\right)^2-4a^2b^2\)
\(=\left(a^2-2ab+b^2\right)\left(a^2+2ab+b^2\right)\)
\(=\left(a-b\right)^2\cdot\left(a+b\right)^2\)
c) \(a^4-b^4=\left(a-b\right)\left(a+b\right)\left(a^2+b^2\right)\)
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Ta có: 9 x 2 - 1 = ( 3 x ) 2 - 1 2 = ( 3 x - 1 ) ( 3 x + 1 )
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Ta có: 9 x 2 - 1 = ( 3 x ) 2 - 1 2 = ( 3 x - 1 ) ( 3 x + 1 )
\(8-27x^3\)
\(=2^3-\left(3x\right)^3\)
\(=\left(2-3x\right)\left(4+6x+9x^2\right)\)
a) \(8-27x^3=\left(2-x\right)\left(4+6x+9x^2\right)\)
b) \(27+27x+9x^2+x^3=\left(3+x\right)^3\)
c) \(x^3+8y^3=\left(x+2y\right)\left(x^2-2xy+4y^2\right)\)