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a: =(2x-3y)^2-4(2x-3y)
=(2x-3y)(2x-3y-4)
b: =3x^2+21x-x-7
=(x+7)(3x-1)
c: =(3x-1)^4+2(3x-1)^2+1
=[(3x-1)^2+1]^2
d: =2x^3-2x^2-x^2+x+x-1
=(x-1)(2x^2-x+1)
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\(y^2-12y+36-144x^2=\left(y-6\right)^2-\left(12x\right)^2=\left(y-12x-6\right)\left(y+12x-6\right)\)
\(=\left(y^2-12y+36\right)-144x^2=\left(y-6\right)^2-144x^2=\left(y-12x-6\right)\left(y+12x-6\right)\)
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\(12y-9x^2+36-3x^2y\)
\(=\left(36-9x^2\right)-\left(3x^2y-12y\right)\)
\(=-9\left(x^2-4\right)-3y\left(x^2-4\right)\)
\(=\left(-3\right)\left(x-2\right)\left(x+2\right)\left(3+y\right)\)
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Sửa: `+12y^2 -> -12y^2`
\(7x^2-5xy-12y^2\\ =7x^2+7xy-12xy-12y^2\\ =7x\left(x+y\right)-12y\left(x+y\right)\\ =\left(7x-12y\right)\left(x+y\right)\)
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\(8x+12y-32x^2y^2\)
\(=4\left(2x+3y-8xy\right)\)
\(8x+12y-32x^2y^2\)
\(=4\left(2x+3y-8x^2y^2\right)\)
thế này thì đã đúng chưa?