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![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,=\left(x-3y\right)^2-16=\left(x-3y-4\right)\left(x-3y+4\right)\\ b,=4\left(x^2-6y^3\right)\\ c,=x^2-3x-5x+15=\left(x-3\right)\left(x-5\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(3xy-6xy^2=3xy\left(1-2y\right)\)
b) \(3x^3+6x^2+3x=3x\left(x^2+2x+1\right)=3x\left(x+1\right)^2\)
c) \(x^3-x^2+2\)
d) \(x^2+4x+4-y^2=\left(x^2+4x+4\right)-y^2=\left(x+2\right)^2-y^2=\left(x-y+2\right)\left(x+y+2\right)\)
e) \(x^3+4x^2+4x=x\left(x^2+4x+4\right)=x\left(x+2\right)^2\)
f) \(x^2+2x+1-9y^2=\left(x+1\right)^2-\left(3y\right)^2=\left(x-3y+1\right)\left(x+3y+1\right)\)
g) \(6x^2-12x=6x\left(x-2\right)\)
h) \(x^3-2x^2+x=x\left(x^2-2x+1\right)=x\left(x-1\right)^2\)
i) \(x^2-2xy+y^2-9=\left(x-y\right)^2-3^2=\left(x-y-3\right)\left(x-y+3\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(x^2-2xy+y^2-2x+2y\)
\(=\left(x-y\right)^2-2\left(x-y\right)\)
\(=\left(x-y\right)\left(x-y-2\right)\)
b) Ta có: \(x^2-4x+4-x^2y+2xy\)
\(=\left(x-2\right)^2-xy\left(x-2\right)\)
\(=\left(x-2\right)\left(x-2-xy\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(x^3+2x^2-3x-6\)
\(=x^2\left(x+2\right)-3\left(x+2\right)\)
\(=\left(x^2-3\right)\left(x+2\right)\)
b) \(5x^2\left(x-1\right)-10xy\left(x-1\right)-5y^2\left(1-x\right)\)
\(=5x^2\left(x-1\right)-10xy\left(x-1\right)+5y^2\left(x-1\right)\)
\(=\left(5x^2-10xy+5y^2\right)\left(x-1\right)\)
\(=5\left(x^2-2xy+y^2\right)\left(x-1\right)\)
\(=5\left(x-y\right)^2\left(x-1\right)\)
c) \(x^2-6xy+9y^2-9\)
\(=\left(x-3\right)^2-3^2\)
\(=\left(x-3-3\right)\left(x-3+3\right)\)
\(\left(x-6\right)x\)
cái thứ 2 và 5 ko hiểu j nên ko làm
mk làm lun nha
1,= x(x^2-3)+2(x^2-3)
= (x+2)(x^2-3)
2.= 2ac(a-b)- d(a-b)
= (2ac-d)(a-b)
3,= (x-1)(5x^2-10xy+5x^2)
= 5(x-1)(x^2-2xy+y^2)
= 5(x-1)(x-y)^2
4, = (x^2-6xy+9y^2)-9
= (x-3y)^2-3^2
= (x-3y+3)(x-3y-3)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x^2-2xy+y^2-a^2+4ab-4b^2\)
\(=\left(x-y\right)^2-\left(a-2b\right)^2\)
\(=\left(x-y-a+2b\right)\left(x-y+a-2b\right)\)
hk tốt
^^
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(x^2y^2-x^2+6xy-9y^2\)
\(=x^2y^2-\left(x^2-6xy+y^2\right)\)
\(=\left(xy\right)^2-\left(x-3y\right)^2\)
\(=\left(xy-x+3y\right)\left(xy+x-3y\right)\)
b) Ta có: \(9-x^2+2xy-y^2\)
\(=9-\left(x^2-2xy+y^2\right)\)
\(=9-\left(x-y\right)^2\)
\(=\left(9-x+y\right)\left(9+x-y\right)\)
36x2-12x+1-y2=(36x2-12x+1)-y2=(6x-1)2-y2=(6x-1+y)(6x-1-y)
a2-2a+1-49b2=(a2-2a+1)-49b2=(a-1)2-(7b)2=(a-1-7b)(a-1+7b)