Câu hỏi của Strangerdaner

Question

Mình cần giải 2 bài Thực hiện phép tính này ạ

Van Toan · Accepted Answer

$a,\dfrac{-13}{5}-\dfrac{-7}{15}.\dfrac{120}{63}+\dfrac{4}{5}\
=\dfrac{-13}{5}+\dfrac{8}{9}+\dfrac{4}{5}\
=\dfrac{-77}{45}+\dfrac{4}{5}\
=\dfrac{-41}{45}\
b.\left(7\dfrac{5}{9}+2\dfrac{2}{3}\right)-5\dfrac{2}{9}\
=\left(\dfrac{68}{9}+\dfrac{8}{3}\right)-\dfrac{47}{9}\
=\dfrac{92}{9}-\dfrac{47}{9}\
=5$Câu trả lời: $a,\dfrac{-13}{5}-\dfrac{-7}{15}.\dfrac{120}{63}+\dfrac{4}{5}\
=\dfrac{-13}{5}+\dfrac{8}{9}+\dfrac{4}{5}\
=\dfrac{-77}{45}+\dfrac{4}{5}\
=\dfrac{-41}{45}\
b.\left(7\dfrac{5}{9}+2\dfrac{2}{3}\right)-5\dfrac{2}{9}\
=\left(\dfrac{68}{9}+\dfrac{8}{3}\right)-\dfrac{47}{9}\
=\dfrac{92}{9}-\dfrac{47}{9}\
=5$

Sahara · Answer

2)$-\dfrac{13}{5}--\dfrac{7}{15}.\dfrac{120}{63}+\dfrac{4}{5}$$=-\dfrac{13}{5}+\dfrac{7.15.8}{15.9.7}+\dfrac{4}{5}$$=-\dfrac{13}{5}+\dfrac{8}{9}+\dfrac{4}{5}$$=\left(-\dfrac{13}{5}+\dfrac{4}{5}\right)+\dfrac{8}{9}$$=-\dfrac{9}{5}+\dfrac{8}{9}$$=\dfrac{-81+40}{45}=-\dfrac{41}{45}$3)$\left(7\dfrac{5}{9}+2\dfrac{2}{3}\right)-5\dfrac{2}{9}$$=\left(7\dfrac{5}{9}-5\dfrac{2}{9}\right)+2\dfrac{2}{3}$$=2\dfrac{1}{3}+2\dfrac{2}{3}$$=5$Câu trả lời: 2)$-\dfrac{13}{5}--\dfrac{7}{15}.\dfrac{120}{63}+\dfrac{4}{5}$$=-\dfrac{13}{5}+\dfrac{7.15.8}{15.9.7}+\dfrac{4}{5}$$=-\dfrac{13}{5}+\dfrac{8}{9}+\dfrac{4}{5}$$=\left(-\dfrac{13}{5}+\dfrac{4}{5}\right)+\dfrac{8}{9}$$=-\dfrac{9}{5}+\dfrac{8}{9}$$=\dfrac{-81+40}{45}=-\dfrac{41}{45}$3)$\left(7\dfrac{5}{9}+2\dfrac{2}{3}\right)-5\dfrac{2}{9}$$=\left(7\dfrac{5}{9}-5\dfrac{2}{9}\right)+2\dfrac{2}{3}$$=2\dfrac{1}{3}+2\dfrac{2}{3}$$=5$

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