![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(M=\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}.\left(2^{20}+1\right)}{2^{30}.\left(2^{20}+1\right)}=2^{10}=1024\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:1+2+3+....+n (Gồm n số hạng)
=> (n+1) . n : 2 =820
=>(n+1).n=820.2
=>(n+1).n=1640
=>(n+1).n=40.41
=>n =40
Vậy n =40
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Tổng trên có số số hạng là:
(n - 1): 1 + 1 = n (số)
Tổng trên là:
(n+1)n : 2 = 820
=> (n+1)n = 820. 2 = 1640 = 40 . 41
=> n = 40
![](https://rs.olm.vn/images/avt/0.png?1311)
Trả lời
a) 9 . 24 . 25 = 9 . 600 = 5400
b) 12 . 125 . 54 = 1500 . 54 = 81000
c) 64 . 125 . 875 = 8000 . 875 = 7000000
d) 425 . 7 . 4 - 170 . 60 = 11900 - 10200 = 1700
e) 8 . 9 . 14 . 6 . 17 . 12 . 19 . 4 . 18 =
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,125^5:25^3=\left(5^3\right)^5:\left(5^2\right)^3=5^{15-6}=5^9\)
\(b,27^6:9^3=\left(3^3\right)^6:\left(3^2\right)^3=3^{18-6}=3^{12}\)
\(c,4^{20}:2^{15}=\left(2^2\right)^{20}:2^{15}=2^{40-15}=2^{25}\)
\(d,24^n:2^{2n}=4^n.6^n:4^n=6^n\)
\(e,64^4.16^5:4^{20}=\left(2^6\right)^4.\left(2^4\right)^5:\left(2^2\right)^{20}=2^{24+20-40}=2^4=16\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(M=\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(\Leftrightarrow M=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}\)
\(\Leftrightarrow M=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}\)
\(\Leftrightarrow M=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)
\(\Leftrightarrow M=\dfrac{2^{40}}{2^{30}}\)
\(\Leftrightarrow M=2^{10}.\)