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\(b,\left(x+5\right)^2=100\)
TH1:\(\left(x+5\right)^2=10^2\)
\(\Rightarrow x+5=10\\ \Rightarrow x=10-5\\ \Rightarrow x=5\)
TH2:\(\left(x+5\right)^2=\left(-10\right)^2\)
\(\Rightarrow x+5=-10\\ \Rightarrow x=-10-5\\ \Rightarrow x=-15\)
\(c,\left(2x-4\right)^2=0\\ \Rightarrow2x-4=0\\ \Rightarrow2x=0+4\\ \Rightarrow x=2:2\\ \Rightarrow x=1\)
\(d,\left(x-1\right)^3=-27\\ \Rightarrow\left(x-1\right)^3=\left(-3\right)^3\\ \Rightarrow x-1=-3\\ \Rightarrow x=-3+1\\ \Rightarrow x=-2\)
b) (x+5)2=100
(x+5)2=102
x+5=10
x=10-5
x=5
c) (2x-4)2=0
2x-4=0
2x=4
x=4:2
x=\(\pm\)2
d)(x-1)3=-27
(x-1)3=-33
x-1=-3
x=-3+1
x=-2
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b: \(=\dfrac{1}{13}\left(\dfrac{10}{9}+\dfrac{27}{11}\right)+\dfrac{11}{13}=\dfrac{1}{13}\cdot\dfrac{353}{99}+\dfrac{11}{13}=\dfrac{1442}{1287}\)
c: \(=\dfrac{-5}{7}\left(\dfrac{3}{11}+\dfrac{8}{11}\right)+\dfrac{9}{7}=\dfrac{-5}{7}+\dfrac{9}{7}=\dfrac{4}{7}\)
d: \(=\dfrac{-5}{-5}\cdot\dfrac{13}{13}\cdot\dfrac{5}{9}\cdot\left(-18\right)=\dfrac{5}{9}\cdot\left(-18\right)=-10\)
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`@OvOpytago`
`a,``-1/8+(-5/3)=-43/24`
`b,``-6/35.-49/54=7/35`
`c,``-4/5:3/4`
`=>``-4/5xx4/3`
`=>``-16/15`
giúp ạ. chỉ cần làm từ bài 3 đến bài 6 thôi ạ:
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d: =64+216+343+2=625=25^2