làm hộ câu g bài 3
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3 tháng 12 2021
Bài 16:
\(e,\left(6n+11\right)⋮\left(2n+3\right)\\ \Rightarrow\left[3\left(2n+3\right)+2\right]⋮\left(2n+3\right)\\ \Rightarrow2⋮\left(2n+3\right)\\ \Rightarrow2n+3\inƯ\left(2\right)=\left\{-2;-1;1;2\right\}\\ \Rightarrow n\in\varnothing\left(n\in N\right)\\ g,\left(3n+5\right)⋮\left(2n+1\right)\\ \Rightarrow\left(6n+10\right)⋮\left(2n+1\right)\\ \Rightarrow\left[3\left(2n+1\right)+7\right]⋮\left(2n+1\right)\\ \Rightarrow7⋮\left(2n+1\right)\\ \Rightarrow2n+1\inƯ\left(7\right)=\left\{-7;-1;1;7\right\}\\ \Rightarrow n\in\left\{0;3\right\}\left(n\in N\right)\)
23 tháng 12 2021
\(xy+x+y=4\\ x\left(y+1\right)+y+1=4+1=5\\ \left(x+1\right)\left(y+1\right)=5\)
| \(x+1\) | \(5\) | \(1\) | \(-1\) | \(-5\) |
| \(y+1\) | \(1\) | \(5\) | \(-5\) | \(-1\) |
| \(x\) | \(4\) | \(0\) | \(-2\) | \(-6\) |
| \(y\) | \(0\) | \(4\) | \(-6\) | \(-2\) |
13 tháng 6 2021
Bài 3:
a) \(\dfrac{3}{4}.\dfrac{16}{9}-\dfrac{7}{5}:\dfrac{-21}{20}=\dfrac{4}{3}-\dfrac{-4}{3}=\dfrac{8}{3}\)
b) \(2\dfrac{1}{3}-\dfrac{1}{3}.\left[\dfrac{-3}{2}+\left(\dfrac{2}{3}+0,4.5\right)\right]\)
\(=\dfrac{7}{3}-\dfrac{1}{3}.\left[\dfrac{-3}{2}+\left(\dfrac{2}{3}+\dfrac{2}{5}.5\right)\right]\)
\(=\dfrac{7}{3}-\dfrac{1}{3}.\left[\dfrac{-3}{2}+\left(\dfrac{2}{3}+2\right)\right]\)
\(=\dfrac{7}{3}-\dfrac{1}{3}.\left[\dfrac{-3}{2}+\dfrac{8}{3}\right]\)
\(=\dfrac{7}{3}-\dfrac{1}{3}.\dfrac{7}{6}\)
\(=\dfrac{7}{3}-\dfrac{7}{18}\)
\(=\dfrac{35}{18}\)
c) \(\left(20+9\dfrac{1}{4}\right):2\dfrac{1}{4}=\left(20+\dfrac{37}{4}\right):\dfrac{9}{4}=\dfrac{117}{4}:\dfrac{9}{4}=13\)
d) \(\left(6-2\dfrac{4}{5}\right).3\dfrac{1}{8}-1\dfrac{3}{5}:\dfrac{1}{4}\)
\(=\left(6-\dfrac{14}{5}\right).\dfrac{25}{8}-\dfrac{8}{5}:\dfrac{1}{4}\)
\(=\dfrac{16}{5}.\dfrac{25}{8}-\dfrac{32}{5}\)
\(=10-\dfrac{32}{5}\)
\(=\dfrac{18}{5}\)
e) \(\dfrac{32}{15}:\left(-1\dfrac{1}{5}+1\dfrac{1}{3}\right)=\dfrac{32}{15}:\left(\dfrac{-6}{5}+\dfrac{4}{3}\right)=\dfrac{32}{15}:\dfrac{2}{15}=16\)
g) \(0,2.\dfrac{15}{36}-\left(\dfrac{2}{5}+\dfrac{2}{3}\right):1\dfrac{1}{5}\)
\(=\dfrac{1}{5}.\dfrac{5}{12}-\dfrac{16}{15}:\dfrac{6}{5}\)
\(=\dfrac{1}{12}-\dfrac{8}{9}\)
\(=\dfrac{-29}{36}\)
h) \(1\dfrac{13}{15}.0,75-\left(\dfrac{8}{15}+0,25\right).\dfrac{24}{27}\)
\(=\dfrac{28}{15}.\dfrac{3}{4}-\left(\dfrac{8}{15}+\dfrac{1}{4}\right).\dfrac{8}{9}\)
\(=\dfrac{7}{5}-\dfrac{47}{60}.\dfrac{8}{9}\)
\(=\dfrac{7}{5}-\dfrac{94}{135}\)
\(=\dfrac{19}{27}\)
g) \(5:\left(4\dfrac{3}{4}-1\dfrac{25}{28}\right)-1\dfrac{3}{8}:\left(\dfrac{3}{8}+\dfrac{9}{20}\right)\)
\(=5:\left(\dfrac{19}{4}-\dfrac{53}{28}\right)-\dfrac{11}{8}:\dfrac{33}{40}\)
\(=5:\dfrac{20}{7}-\dfrac{5}{3}\)
\(=\dfrac{7}{4}-\dfrac{5}{3}\)
\(=\dfrac{1}{12}\)
TQ
13 tháng 6 2021
\(a\)) \(\dfrac{3}{4}.\dfrac{16}{9}-\dfrac{7}{5}:\dfrac{-21}{20}\)
\(=\dfrac{4}{3}-\dfrac{7}{5}.\dfrac{-20}{21}\)
\(=\dfrac{4}{3}-\dfrac{-4}{3}\)
\(=\dfrac{8}{3}\)
\(=2\dfrac{2}{3}\)
ai làm hộ mình câu 3 với ạ
NK
1
ND
Nguyễn Đức Trí
VIP
3 tháng 8 2023
\(A=3+3^2+3^3+...+3^{2023}\)
\(\Rightarrow A+1=1+3+3^2+3^3+...+3^{2023}\)
\(\Rightarrow A+1=\dfrac{3^{2023+1}-1}{3-1}=\dfrac{3^{2024}-1}{2}\)
\(\Rightarrow A=\dfrac{3^{2024}-1}{2}-1=\dfrac{3^{2024}-3}{2}=\dfrac{3\left(3^{2023}-1\right)}{2}\)
Bài 3:
g: \(\Leftrightarrow3\cdot4^x-4^x\cdot16=-80\)
\(\Leftrightarrow4^x=\dfrac{80}{13}\)
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