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Mai thi rồi
\(n_{Fe_2O_3}=\dfrac{m}{M}=\dfrac{3,2}{160}=0,02mol\)
\(Fe_2O_3+3H_2\rightarrow\left(t^o\right)2Fe+3H_2O\)
0,02 0,06 0,04 ( mol )
\(V_{H_2}=n.22,4=0,06.22,4=1,334l\)
\(m_{Fe}=n.M=0,04.56=2,24g\)
nFe2O3 = 3,2/160 = 0,02 (mol)
PTHH: Fe2O3 + 3H2 -> (t°) 2Fe + 3H2O
Mol: 0,02 ---> 0,06 ---> 0,04
VH2 = 0,06 . 22,4 = 1,344 (l)
mFe = 0,04 . 56 = 2,24 (g)
a, \(Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\)
b, \(n_{Fe_2O_3}=\dfrac{24}{160}=0,15\left(mol\right)\)
Theo PT: \(n_{H_2}=3n_{Fe_2O_3}=0,45\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,45.22,4=10,08\left(l\right)\)
c, n\(n_{Fe}=2n_{Fe_2O_3}=0,3\left(mol\right)\)
PT: \(Fe+2HCl\rightarrow FeCl_2+H_2\)
Theo PT: \(n_{HCl}=2n_{Fe}=0,6\left(mol\right)\Rightarrow V_{HCl}=\dfrac{0,6}{1,5}=0,4\left(M\right)\)
\(n_{ZnO}=\dfrac{m}{M}=\dfrac{16,2}{65+16}=0,2\left(mol\right)\)
a) \(PTHH:Zn+H_2O\rightarrow ZnO+H_2\)
1 1 1 1
0,2 0,2 0,2 0,2
b) \(V_{H_2}=n.24,79=0,2.24,79=4,958\left(l\right)\)
c) \(m_{Zn}=n.M=0,2.65=13\left(g\right).\)
a, \(Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\)
b, \(n_{Fe}=\dfrac{33,6}{56}=0,6\left(mol\right)\)
Theo PT: \(n_{Fe_2O_3}=\dfrac{1}{2}n_{Fe}=0,3\left(mol\right)\Rightarrow m_{Fe_2O_3}=0,3.160=48\left(g\right)\)
c, \(n_{H_2}=\dfrac{3}{2}n_{Fe}=0,9\left(mol\right)\Rightarrow V_{H_2}=0,9.22,4=20,16\left(l\right)\)
\(n_{Fe_2O_3=}=\dfrac{24}{160}=0,15mol\)
\(Fe_2O_3+3H_2\rightarrow2Fe+3H_2O\)
0,15 0,45 0,3 0,45
\(V_{H_2}=0,45\cdot224,=10,08l\)
\(m_{Fe}=0,3\cdot56=16,8g\)
\(n_{Fe_3O_4}=\dfrac{24}{232}=\dfrac{3}{29}\left(mol\right)\)
PTHH :
\(Fe_3O_4+4H_2\underrightarrow{t^o}3Fe+4H_2O\)
3/29 9/29
\(Fe+2HCl\rightarrow FeCl_2+H_2\uparrow\)
9/29 18/29
\(c,V_{HCl}=\dfrac{\dfrac{18}{29}}{1,5}=\dfrac{12}{29}\left(l\right)\)
a, \(Fe_3O_4+4H_2\underrightarrow{t^o}3Fe+4H_2O\)
b, \(n_{Fe}=\dfrac{11,2}{56}=0,2\left(mol\right)\)
Theo PT: \(n_{Fe_3O_4}=\dfrac{1}{3}n_{Fe}=\dfrac{1}{15}\left(mol\right)\Rightarrow m_{Fe_3O_4}=\dfrac{1}{15}.232=\dfrac{232}{15}\left(g\right)\)
c, \(n_{H_2}=\dfrac{4}{3}n_{Fe}=\dfrac{4}{15}\left(mol\right)\Rightarrow V_{H_2}=\dfrac{4}{15}.22,4=\dfrac{448}{75}\left(l\right)\)
d, \(Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(n_{Zn}=n_{H_2}=\dfrac{4}{15}\left(mol\right)\Rightarrow m_{Zn}=\dfrac{4}{15}.65=\dfrac{52}{3}\left(g\right)\)
\(n_{HCl}=2n_{H_2}=\dfrac{8}{15}\left(mol\right)\Rightarrow m_{HCl}=\dfrac{8}{15}.36,5=\dfrac{292}{15}\left(g\right)\)
\(n_{Fe_2O_3}=\frac{3,2}{160}=0,02\left(mol\right)\)
a, \(Fe_2O_3+3H_2-->2Fe+3H_2O\left(1\right)\)
b, Theo (1), \(n_{H_2}=3n_{Fe_2O_3}=0,06\left(mol\right)\)
=> \(V_{H_2}=0,06.22,4=1,344\left(l\right)\)
c, theo (1) \(n_{Fe}=2n_{Fe_2O_3}=0,04\left(mol\right)\)
=> \(m_{Fe}=0,04.56=2,24\left(g\right)\)