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Ta có: a = 2002.2002 = 2002.(2000 + 2) = 2002.2000 + 2002.2
b = 2000.2004 = 2000.(2002 + 2) = 2000.2002 + 2000.2
Do 2002. 2000 = 2000. 2002 và 2002.2 > 2000.2
Nên a > b
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a=2002.2002=2002.(2000+2)=2002.2000+2002.2
b=2000.2004=2000.(2002+2)=2000.2002+2000.2
Ta thấy:2002.2000 = 2000.2002
2002.2 > 2000.2
Vậy a>b
a=2002.(2000+2)=2002.2000+4004 b=2000.(2002+2)=2000.2002+4000 Vậy a>b
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a = 2002 . 2002
a = (2000 + 2) . 2002
a = 2000.2002 + 2.2002
b = 2000 . 2004
b = 2000 . (2002 + 2)
b = 2000.2002 + 2000.2
Vì 2.2002 > 2000.2
=> 2000.2002 + 2.2002 > 2000.2002 + 2000.2
=> a > b
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\(A>\left(2021^2-1\right)\cdot2021=\left(2021-1\right)\left(2021+1\right)\cdot2021=B\)
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\(B=2020.2021.2022=\left(2021-1\right).2021.\left(2021+1\right)=\left[\left(2021-1\right)\left(2021+1\right)\right].2021=\left(2021^2-2021+2021-1\right).2021=\left(2021^2-1\right).2021=2021^3-2021< 2021^3=A\)
vậy B<A
\(B=2020.2021.2022\\ B=\left(2021-1\right).2021.\left(2021+1\right)\\ B=\left(2021^2-1\right).2021\\ B=2021^3-2021\\ \Rightarrow A>B\)
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Tham khảo:https://hoc24.vn/cau-hoi/cho-a-20213-va-b-202020212022-khong-tinh-cu-the-cac-gia-tri-cua-a-va-b-hay-so-sanh-a-va-b-ai-lam-giup-mik-voi.3007463332171
A = 2016 x 2016
B = 2018 x 2014
A = 2016 x ( 2014 +2 )
A= 2016 x 2014 + 2016 x 2
B = 2018 x 2014
B = ( 2016 + 2 ) x 2014
B = 2016 x 2014 + 2014 x 2
Vì 2016 x 2014 = 2016 x 2014, mà 2016 x 2 > 2014 x 2
Vậy A > B
Ta có: b= 2018.2014 = (2016+2)(2016-2)= 20162 - 4 < 20162= 2016.2016=a