Question

[Phượng Phạm]

giupsp t voiii

Answer 1

[Nguyễn Việt Lâm]

a.

\(\dfrac{3}{4}+\dfrac{1}{4}:x=-3\)

\(\dfrac{1}{4}:x=-3-\dfrac{3}{4}\)

\(\dfrac{1}{4}:x=-\dfrac{15}{4}\)

\(x=\dfrac{1}{4}:\left(-\dfrac{15}{4}\right)\)

\(x=-\dfrac{1}{15}\)

b.

\(\dfrac{4}{7}x-x=\dfrac{-9}{14}\)

\(\Leftrightarrow\left(\dfrac{4}{7}-1\right)x=\dfrac{-9}{14}\)

\(\Leftrightarrow-\dfrac{3}{7}x=-\dfrac{9}{14}\)

\(\Leftrightarrow x=-\dfrac{9}{14}:\left(-\dfrac{3}{7}\right)\)

\(\Leftrightarrow x=\dfrac{3}{2}\)

c.

\(\dfrac{1}{2}x+\dfrac{3}{5}x=\dfrac{-2}{3}\)

\(\Leftrightarrow\left(\dfrac{1}{2}+\dfrac{3}{5}\right)x=-\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{11}{10}x=-\dfrac{2}{3}\)

\(\Leftrightarrow x=-\dfrac{2}{3}:\dfrac{11}{10}\)

\(\Leftrightarrow x=-\dfrac{20}{33}\)

Answer 2

[Akai Haruma]

Lời giải:
n. $\frac{1}{4}:x=-3-\frac{3}{4}=\frac{-15}{4}$

$x=\frac{1}{4}: \frac{-15}{4}=\frac{-1}{15}$

o.

$\frac{4}{7}x-x=\frac{-9}{14}$

$x(\frac{4}{7}-1)=\frac{-9}{14}$

$x.\frac{-3}{7}=\frac{-9}{14}$

$x=\frac{-9}{14}: \frac{-3}{7}=\frac{3}{2}$

p.

$\frac{1}{2}x+\frac{3}{5}x=\frac{-2}{3}$

$x(\frac{1}{2}+\frac{3}{5})=\frac{-2}{3}$

$x.\frac{11}{10}=\frac{-2}{3}$

$x=\frac{-2}{3}: \frac{11}{10}=\frac{-20}{33}$