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12x - 10x + 54 = 86
\(\Rightarrow\)12x - 10x = 86 - 54
\(\Rightarrow\)2x = 32
\(\Rightarrow\)x = 32 : 2
\(\Rightarrow\) x= 16
12x-10x+54=86
=(12-10)x+54=86
(12-10)x =32
2x =32
x =32chia2
x =16
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a,5mũ 36=(5mũ3)mũ12=125 mũ12
11^24=(11^2)12=121^12
vì 121<125 nên 5^36>11^24
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 128 - 3(x + 4) = 23
3(x + 4) = 128 -23
3(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
\(a.128-3\left(x+4\right)=23.\)
\(3\left(x+4\right)=128-23\)
\(3\left(x+4\right)=105\)
\(x+4=105:3=35\)
\(x=35-4=31\)
\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)
\(\left(4x+28\right)\cdot3=175-55=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
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\(3+3^2+3^3+...+3^{2012}\)
\(=\left(3+3^2+3^3+3^4\right)+...+\left(3^{2009}+3^{2010}+3^{2011}+3^{2012}\right)\)
\(=3\left(1+3+3^2+3^3\right)+...+3^{2009}\left(1+3+3^2+3^3\right)\)
\(=40\left(3+...+3^{2009}\right)⋮40\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Mình làm ngắn gọn nhé.
\(A=1+2+2^2+...+2^{50}\)
\(\Rightarrow2A=2+2^2+...+2^{51}\)
\(\Rightarrow2A-A=2+2^2+...+2^{51}-1-2-2^2-...-2^{50}\)
\(\Rightarrow A=2^{51}-1\)
\(B=1+3+...+3^{66}\)
\(3B=3+3^2+...+3^{67}\)
\(2B=3+3^2+...+3^{67}-1-3-...-3^{66}\)
\(2B=3^{67}-1\)
\(B=\frac{3^{67}-1}{2}\)
ghi lại đề:
12.x - 33 = 32 . 33
=> 12.x - 33 = 243
=> 12x = 243 + 33
12x = 276
=> x = 276 : 12
x = 23
chúc bạn học tốt!! ^^
ok mk nhé!!! 356535645746857579763563653645645654645657657657858753453465465756765
12x - 33 = 32.33
12x - 33 = 35
12x - 33 = 243
12x = 243+33
12x = 276
x= 276:12
x = 23
vậy x = 23