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\(\left\{{}\begin{matrix}x+y=5\\\dfrac{3}{5}+\dfrac{2}{x-y}=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+y=5\\\dfrac{2}{x-y}=\dfrac{12}{5}\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x+y=5\\6\left(x-y\right)=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+y=5\\x-y=\dfrac{5}{6}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x=\dfrac{35}{6}\\y=x-\dfrac{5}{6}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{35}{12}\\y=\dfrac{25}{12}\end{matrix}\right.\)
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1) ĐKXĐ: \(x\ge-5\)
\(pt\Leftrightarrow x+5=9\Leftrightarrow x=9-5=4\left(tm\right)\)
2) ĐKXĐ: \(x\ge3\)
\(pt\Leftrightarrow3\sqrt{x-3}-\sqrt{x-3}=6\)
\(\Leftrightarrow2\sqrt{x-3}=6\Leftrightarrow\sqrt{x-3}=3\)
\(\Leftrightarrow x-3=9\Leftrightarrow x=12\left(tm\right)\)
3) ĐKXĐ: \(x\ge-1\)
\(pt\Leftrightarrow\sqrt{\left(x+1\right)^2}-2\sqrt{x+1}=0\)
\(\Leftrightarrow x+1-2\sqrt{x+1}=0\)
\(\Leftrightarrow\sqrt{x+1}\left(\sqrt{x+1}-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=0\\x+1=4\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=-1\left(tm\right)\\x=3\left(tm\right)\end{matrix}\right.\)
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\(\hept{\begin{cases}\frac{y}{2}-\frac{\left(x+y\right)}{5}=0,1\\\frac{y}{5}-\frac{\left(x-y\right)}{2}=0.1\end{cases}}\)
\(\hept{\begin{cases}\frac{\left(x+y\right)}{5}=\frac{y-0,2}{2}\\\frac{y}{5}-\frac{\left(x-y\right)}{2}=0,1\end{cases}}\)
\(\hept{\begin{cases}x+y=\frac{5y-1}{2}\\\frac{y}{5}-\frac{\left(x-y\right)}{2}=0,1\end{cases}}\)
\(\hept{\begin{cases}x=\frac{5y-1}{2}-\frac{2y}{2}=\frac{3y-1}{2}\\\frac{y}{5}-\frac{\left(x-y\right)}{2}=0,1\end{cases}}\)
Ta thay x vào biểu thức \(\frac{y}{5}-\frac{\left(x-y\right)}{2}\)ta đc
\(\frac{y}{5}-\frac{\left(\frac{3y-1}{2}-y\right)}{2}=0,1\)
\(\frac{3y-1-2y}{2}=\frac{y}{5}-\frac{0,5}{5}\)
\(\frac{y-1}{2}=\frac{y-0,5}{5}\)
\(5y-5=2y-1\Leftrightarrow5y-5-2y+1=0\Leftrightarrow3y-4=0\Leftrightarrow y=\frac{4}{3}\)
Thay y vào biểu thức \(\frac{3y-1}{2}\)ta đc
\(x=\frac{3.\frac{4}{3}-1}{2}=\frac{3}{2}\)
Vậy \(\left\{x;y\right\}=\left\{\frac{3}{2};\frac{4}{3}\right\}\)
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nhập PT vào máy tính, sử dụng dầu "=" ô nút CALC.
sau khi nhập xong, nhấn SHIFT,CALC, rồi nhấn dấu =
Ta được x=-1,322875656
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\(\left\{{}\begin{matrix}\dfrac{5}{y}-\dfrac{7}{y}=9\\\dfrac{4}{x}-\dfrac{9}{y}=35\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{-2}{y}=9\\\dfrac{4}{x}-\dfrac{9}{y}=35\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=-\dfrac{2}{9}\\\dfrac{4}{x}-\dfrac{9}{-\dfrac{2}{9}}=35\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=-\dfrac{2}{9}\\\dfrac{4}{x}=-\dfrac{11}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=-\dfrac{2}{9}\\x=-\dfrac{8}{11}\end{matrix}\right.\)
Vậy....