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\(2^4.5-\left[31-9^2\right]=16.5-\left(31-81\right)=80-\left(-50\right)=130\)
\(2^4\).5-[1.31-(13-4)^2]
=16.5-[1.31-81]
=16.5-[31-81]
=16.5-(-50)
=80-(-50)
=130
![](https://rs.olm.vn/images/avt/0.png?1311)
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Bài 6:
\(\Leftrightarrow6n+4⋮2n-1\)
\(\Leftrightarrow2n-1\in\left\{1;-1;7;-7\right\}\)
hay \(n\in\left\{1;0;4;-3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(2018^{2018}=2018^2.\left(2018^4\right)^{504}=\left(\overline{...4}\right).\left(\overline{...6}\right)=\overline{...4}\)
\(2019^{2019}=2019.\left(2019^2\right)^{1009}=2019.\left(\overline{...1}\right)=\overline{...9}\)
Để \(x⋮10\) thì \(\left(\overline{...4}\right)+\left(\overline{...9}\right)+m⋮10\)
\(\Rightarrow\left(\overline{...3}\right)+m⋮10\)
\(\Rightarrow\)m là số tự nhiên có tận cùng là 7
Mà m nhỏ nhất nên m = 7
Vậy m = 7.
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
1:
a: \(\dfrac{-45}{56}< >\dfrac{-55}{67}\)
b: \(\dfrac{-4}{5}=\dfrac{144}{-180}\)
2:
a: \(\dfrac{5}{x}=\dfrac{15}{20}=\dfrac{3}{4}\)
nên x=20/3
b: \(\dfrac{x}{-3}=\dfrac{-27}{x}\)
nên \(x^2=81\)
hay \(x\in\left\{9;-9\right\}\)
c: \(\dfrac{4}{3y-1}=\dfrac{2}{25}\)
nên 3y-1=50
=>3y=51
hay y=17
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ư(60):{ 1;2;3;4;5;6;10;12;15;20;30;60}
Ư(84):{ 1;2;4;6;7;12;14;21;42;84}
Ư(120):{ 1;2;3;4;5;6;8;10;12;15;20;24;30;40;60;120}
ƯC(60;84;120):{ 2;4;6;12}
nhưng vì x_> 6 nên x = 2,4,6
![](https://rs.olm.vn/images/avt/0.png?1311)
Tính phải k nhỉ?
`1)`
`2x + 3x + 5x`
`= (2 + 3 + 5)x`
`= 10x`
`2)`
`2.x - x + 3.x`
`= (2 - 1 + 3)x`
`= 4x`
`3)`
`9.x - 3 - 3.x`
`= (9 - 3)x - 3`
`= 6x - 3`
`4)`
Thiếu dấu, bạn bổ sung thêm
`5)`
`x - 0,2x - 0,1x`
`= (1 - 0,2 - 0,1)x`
`=0,7x`
`6)`
\(\dfrac{7}{2}x-\dfrac{1}{2}x=\left(\dfrac{7}{2}-\dfrac{1}{2}\right)x=3x\)
Bài 1:
1. $2^n+2^{n+3}=144$
$2^n(1+2^3)=144$
$2^n.9=144$
$2^n=144:9=16=2^4\Rightarrow n=4$
2.
$3^n+3^{n+2}=270$
$3^n(1+3^2)=270$
$3^n.10=270$
$3^n=270:10=27=3^3\Rightarrow n=3$
3.
$2^n+2^{n+1}+2^{n+2}+2^{n+3}=960$
$2^n(1+2+2^2+2^3)=960$
$2^n.15=960$
$2^n=960:15=64=2^6$
$\Rightarrow n=6$
4.
$3^n+3^{n+1}+3^{n+2}+3^{n+3}=3240$
$3^n(1+3+3^2+3^3)=3240$
$3^n.40=3240$
$3^n=3240:40=81=3^4\Rightarrow n=4$
Bài 2:
1. $(x+1)^2=49=7^2$
$\Rightarrow x+1=7$
$\Rightarrow x=6$
2.
$(x+2)^3=512=8^3$
$\Rightarrow x+2=8\Rightarrow x=6$
3.
$(x-3)^9=(x-3)$
$\Rightarrow (x-3)^9-(x-3)=0$
$\Rightarrow (x-3)[(x-3)^8-1]=0$
$\Rightarrow x-3=0$ hoặc $(x-3)^8-1=0$
$\Rightarrow x-3=0$ hoặc $(x-3)^8=1=1^8=(-1)^8$
$\Rightarrow x=3$ hoặc $x-3=1$ hoặc $x-3=-1$
$\Rightarrow x=3$ hoặc $x=4$ hoặc $x=2$