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![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\left(\frac{2}{3}\right)^x\right)^3=\frac{27}{8}\)
\(\Rightarrow\left(\frac{2}{3}\right)^x=\frac{3}{2}\)
\(\Rightarrow x=-1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\left(\frac{2}{3}\right)^x\right)^3=\frac{27}{8}\Rightarrow\left(\left(\frac{2}{3}\right)^x\right)^3=\left(\frac{3}{2}\right)^3\Rightarrow\left(\frac{2}{3}\right)^x=\frac{3}{2}\Rightarrow\left(\frac{2}{3}\right)^x=\left(\frac{2}{3}\right)^{-1}\Rightarrow x=-1\)
Giá trị của x thỏa mãn:
\(\left(\frac{1}{2}\right)^{x+4}=\left(\frac{1}{4}\right)^{\frac{3}{2}.x-4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\frac{1}{2}\right)^{x+4}=\left(\frac{1}{4}\right)^{\frac{3}{2}x-4}\)
=> \(\left(\frac{1}{2}\right)^{x+4}=\left(\frac{1}{2}\right)^{2\left(\frac{3}{2}x-4\right)}\)
=> \(\left(\frac{1}{2}\right)^{x+4}=\left(\frac{1}{2}\right)^{3x-8}\)
=> \(x+4=3x-8\)
=> \(3x-8-x=4\)
=> \(2x-8=4\)
=> \(2x=12\)
=> \(x=\frac{12}{2}=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\frac{1}{2}\right)^{-x+4}=\left(\frac{1}{4}\right)^{\frac{3}{2}x-4}\)
=>\(\left(\frac{1}{2}\right)^{-x+4}=\left(\frac{1}{2}\right)^{3x-8}\)
=>-x+4=3x-8
<=>4x=12
<=>x=3
Vậy x=3
\(\left(\frac{1}{4}\right)^{\frac{3}{2}-4}=\left(\frac{1}{2}\right)^{2.\left(\frac{3}{2}-4\right)}=\left(\frac{1}{2}\right)^{-1}\)
; do đó -x + 4 = -1
=> -x = -1 - 4 = -5
=> x = 5