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x^4=6.25^2
\(\Leftrightarrow\)x=\(\sqrt{6.25}\)
\(\Leftrightarrow\)x=-2.5
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Ta có ( x-1)(x-2)(x+2)(x+4) = 0
Vậy có 4 gt x tm x=1 ; x=2 ; x=-2 ; x=-4
Vậy tổng của chúng là -3
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`4/7 xx x -2/3=1/5`
`=> 4/7 xx x = 1/5+2/3`
`=> 4/7 xx x = 3/15 +10/15`
`=> 4/7 xx x =13/15`
`=> x= 13/15 : 4/7`
`=> x=13/15 xx 7/4`
`=> x= 91/60`
`4/7xx` `x-2/3=1/5`
`7/7xx` `x=3/15+10/15`
`4/7xx` `x=13/15`
`x=13/15:4/7`
`x=13/15xx4/7`
`x=91/60`
Vậy `x=91/60`
`@Nae`
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Vi |x^2-5| va |5-x^2| luon lon hon hoac bang 0
\(\Leftrightarrow\)|x^2-5| = 0 va |5-x^2| = 0
\(\Leftrightarrow\)x^2- 5 = 0 va 5- x^2 = 0
\(\Leftrightarrow\)x^2 = 5
\(\Leftrightarrow\)x = 5 ; x = -5
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\(\Rightarrow\orbr{\begin{cases}x^2-5=-5+x^2\\5+x^2=-x^2+5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x^2-x^2=0\\-x^2-x^2=0\end{cases}}\)
\(\Rightarrow x=0\)
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x^2 - 3^2 = 4^2
=> x^2 - 9 = 16
=> x^2 = 16 + 9
=> x^2 = 25
=> x^2 = 5^2
=> x = 5
\(x=-2\)