Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3-x}{5}=\frac{1}{4}\)
\(\Rightarrow4.\left(3-x\right)=5\)
\(\Rightarrow12-4x=5\)
\(\Rightarrow4x=12-5\)
\(\Rightarrow4x=7\)
\(\Rightarrow x=\frac{7}{4}\)
Vậy x = \(\frac{7}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow\frac{1}{2}x-\frac{3}{8}-\frac{2}{5}x=\frac{17}{4}\)
\(\Leftrightarrow\frac{1}{2}x-\frac{2}{5}x=\frac{17}{4}+\frac{3}{8}\)(Bạn tự quy đồng chỗ này)
\(\Leftrightarrow\frac{1}{10}x=\frac{37}{8}\)
\(\Leftrightarrow x=\frac{185}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có \(M=\frac{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{11}}=\frac{3\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{11}\right)}{4\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{11}\right)}=\frac{3}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A. 5(x-11) + 4(x-3) =10
<=>5x -55 + 4x -12 =10
<=>9x -67 =10
<=>9x =10+67 =77
<=>x =77 : 9 =77/9
B.21 - 5 ( x-7) = 2-3(x-5)
<=>21-5x+35 = 2 - 3x +15
<=>-5x + 56 = -3x + 17
<=>-5x +3x=17-56=-39
<=> -2x =-39
<=> x = -39 : -2 =39/2
C.3(2x-1)-7(x+4)=8-9x
<=>6x -4 -7x-28=-9x+8
<=>-x + 9x = 8+4+28=40
<=> 8x = 40
<=> x = 40:8=5
D. l 4-x l =11
<=>\(\orbr{\begin{cases}4-x=11\\4-x=-11\end{cases}}\)<=> \(\orbr{\begin{cases}x=-7\\x=15\end{cases}}\)
E. 5-3 l x+2 l = -28
<=> 3 l x+2 L = -28 -5 =-33
<=> l x+2 l = -33 :3 =11
<=>\(\orbr{\begin{cases}x+2=11\\x+2=-11\end{cases}}\)<=> \(\orbr{\begin{cases}x=9\\-13\end{cases}}\)
T I C K mk nhé!!!^_^
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+....+\frac{1}{x\left(x+1\right)}=\frac{215}{216}\)
\(\Leftrightarrow1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{x}-\frac{1}{x+1}=\frac{215}{216}\)
\(\Leftrightarrow1-\frac{1}{x+1}=\frac{215}{216}\)
\(\Leftrightarrow\frac{1}{x+1}=1-\frac{215}{216}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{216}\)
\(\Leftrightarrow x=216-1=215\)
![](https://rs.olm.vn/images/avt/0.png?1311)
15 - 2 | 4 + 5x | = 59 <=> 2 | 4 + 5x | = -44 <=> | 4 + 5x | = -22
Vì \(\left|4+5x\right|\ge0\) nên không có x thỏa mãn | 4 + 5x | = -22
-------------------------------
TH1: \(x\le\frac{1}{5}\)=>3-x+1-5x=7=>4-6x=7=>-3=6x=>x=-1/2(nhận)
TH2:\(\frac{1}{5}< x\le3\)=>3-x+5x-1=7=>2+4x=7=>4x=5=>x=5/4(nhận)
TH3:x>3=>x-3+5x-1=7=>6x-4=7=>6x=11=>x=11/6(loại)
Vậy x=-1/2 hoặc x=5/4
![](https://rs.olm.vn/images/avt/0.png?1311)
các bạn ơi mình đang cần gấp . Mình chỉ còn 20 phút thui . HUHU
Bài làm :
1) \(\frac{x+11}{4}=\frac{2x+4}{5}\)
\(\Leftrightarrow\left(x+11\right).5=4.\left(2x+4\right)\)
\(\Leftrightarrow5x+55=8x+16\)
\(\Leftrightarrow5x-8x=16-55\)
\(\Leftrightarrow-3x=-39\)
\(\Leftrightarrow x=\frac{-39}{-3}=\frac{39}{3}=13\)
2)\(\frac{x+4}{x+10}=\frac{3}{5}\)
\(\Leftrightarrow\left(x+4\right).5=\left(x+10\right).3\)
\(\Leftrightarrow5x+20=3x+30\)
\(\Leftrightarrow5x-3x=30-20\)
\(\Leftrightarrow2x=10\)
\(\Leftrightarrow x=\frac{10}{2}=5\)
3)\(\frac{x+8}{x+14}=\frac{2}{3}\)
\(\Leftrightarrow\left(x+8\right).3=\left(x+14\right).2\)
\(\Leftrightarrow3x+24=2x+28\)
\(\Leftrightarrow3x-2x=28-24\)
\(\Leftrightarrow x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x}{5}\le\frac{12}{x}\Rightarrow x^2\le60\left(1\right)\)
\(\frac{12}{x}\le\frac{x}{3}\Rightarrow x^2\ge36\left(2\right)\)
Từ (1) và (2)
\(\Rightarrow36\le x^2\le60\) và \(x\in N\)
\(\Rightarrow6\le x\le7,75\)
Vậy \(x=6;7\)
\(\Rightarrow\frac{2x}{4}-\frac{3}{5}=\frac{x}{4}\)
\(\Rightarrow\frac{2x}{4}-\frac{x}{4}=\frac{3}{5}\)
\(\Rightarrow\frac{x}{4}=\frac{3}{5}\)
=> 5x = 12
=> x= 12/5
bn luân sai r