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![](https://rs.olm.vn/images/avt/0.png?1311)
= 25 nha bạn
các bạn tick mình cho tròn 220 điểm hỏi đáp với
\(=\frac{5^3.\left(2^3+2+1\right)}{55}=\frac{5^2.5.11}{5.11}=5^2=25\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lần sau bạn nên viết đề rõ hơn nhé!
Đề: Tính nhanh: \(\frac{10^3+2\cdot5^3+5^3}{55}\)
ta có: \(\frac{10^3+2\cdot5^3+5^3}{55}=\frac{5^3\left(2^3+2+1\right)}{5\cdot11}=\frac{5^3\cdot11}{5\cdot11}=5^2=25\)
Học tốt nhé ^3^
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{10^3+2\times5^3+5^3}{55}\)= \(\frac{1000+2\times125+125}{55}\)= \(\frac{1000+250+125}{55}\)= \(\frac{1250+125}{55}\)= \(\frac{1375}{55}\)= 25.
![](https://rs.olm.vn/images/avt/0.png?1311)
chìu mk lm nha
Giờ mk có việc rồi
Nhớ tick cho mk nha !!!!!
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{10^3+2\cdot5^3+5^3}{55}\)
\(=\frac{\left(5.2\right)^3+5^3\cdot\left(2+1\right)}{55}\)
\(=\frac{5^3\cdot2^3+5^3\cdot3}{55}\)
\(=\frac{5^3\cdot8+5^3\cdot3}{55}\)
\(=\frac{5^3\cdot\left(8+3\right)}{55}\)
\(=\frac{5^3\cdot11}{55}=\frac{5^3}{5}=5^2=25\)
Tick nha
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{10^3+2.5^3+5^3}{55}-\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)\(=\frac{2^3.5^3+2.5^3+5^3}{5.11}-\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{5^3\left(2^3+2+1\right)}{5.11}-\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}=\frac{5^2.11}{11}-\frac{2.6}{3.5}=25-\frac{4}{5}=\frac{121}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left|x\right|-3=4\)
\(\Rightarrow\left|x\right|=4+3\)
\(\Rightarrow\left|x\right|=7\)
\(\Rightarrow x\in\left\{-7;7\right\}\)
\(\frac{10^3+2.5^3+5^3}{55}=\frac{2^3.5^3+5^3\left(1+2\right)}{5.11}=\frac{8.5^3+5^3.3}{5.11}=\frac{5^3\left(8+3\right)}{5.11}\)
\(=\frac{5^3.11}{5.11}=\frac{5^3}{5}=5^2=25\)
Bài 1 :
\(\left|x\right|-3=4\)
\(\left|x\right|=7\)
\(\Rightarrow\orbr{\begin{cases}x=7\\x=-7\end{cases}}\)
Vậy...
Bài 2 :
\(\frac{10^3+2\cdot5^3+5^3}{55}\)
\(=\frac{2^3\cdot5^3+2\cdot5^3+5^3}{5\cdot11}\)
\(=\frac{5^3\cdot\left(2^3+2+1\right)}{5\cdot11}\)
\(=\frac{5^3\cdot11}{5\cdot11}\)
\(=5^2\)
\(\frac{10^3+2.5^3+5^3}{55}\)
\(=\frac{\left(2.5\right)^3+2.5^3+5^3}{5.11}\)
=\(\frac{2^3.5^3+2.5^3+5^3}{5.11}\)
=\(\frac{5^3.\left(2^3+2+1\right)}{5.11}\)
=\(\frac{5^3.\left(8+2+1\right)}{5.11}\)
=\(\frac{5^3.11}{5.11}\)
=\(5^2\)
=25
Chúc bn học tốt !