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\(1,\\ a,\Leftrightarrow4^{5-x}=4^2\Leftrightarrow5-x=2\Leftrightarrow x=3\\ b,\Leftrightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\\ c,\Leftrightarrow2x+1=3\Leftrightarrow x=2\\ 2,\\ a,3^{100}=\left(3^2\right)^{50}=9^{50}\\ b,2^{98}=\left(2^2\right)^{49}=4^{49}< 9^{49}\\ c,5^{30}=5^{29}\cdot5< 6\cdot5^{29}\\ d,3^{30}=\left(3^3\right)^{10}=27^{10}>8^{10}\\ 4,\\ a,\Leftrightarrow5\left(x-10\right)=10\\ \Leftrightarrow x-10=2\Leftrightarrow x=12\\ b,\Leftrightarrow3\left(70-x\right)+5=92\\ \Leftrightarrow3\left(70-x\right)=87\\ \Leftrightarrow70-x=29\\ \Leftrightarrow x=41\\ c,\Leftrightarrow16+x-5=315-230=85\\ \Leftrightarrow x=74\\ d,\Leftrightarrow2^x-5+74=707:\left(16-9\right)=707:7=101\\ \Leftrightarrow2^x=32=2^5\\ \Leftrightarrow x=5\)
a) \(\dfrac{2^6\cdot5^5}{10^5}\)
\(=\dfrac{2^6\cdot5^5}{2^5\cdot5^5}\)
\(=2\)
b) \(\dfrac{3^6\cdot5^7}{15^6}\)
\(=\dfrac{3^6\cdot5^7}{3^6\cdot5^6}\)
\(=5\)
Câu 1:
\(A=\frac{2^5.7+2^5}{2^5.3-2^5}\)= \(\frac{2^5.8}{2^5.2}\)= 4
Vậy A = 4
Câu 2:
\(B=2^3.5^3-3.\left\{400-\left[673-2^3.\left(7^8:7^6+7^0\right)\right]\right\}\)
\(B=8.125-3.\left\{400-\left[673-8.\left(7^2+1\right)\right]\right\}\)
\(B=1000-3.\left\{400-\left[673-8.\left(49+1\right)\right]\right\}\)
\(B=1000-3.\left\{400-\left[673-8.50\right]\right\}\)
\(B=1000-3.\left\{400-\left[673-400\right]\right\}\)
\(B=1000-3.\left\{400-273\right\}\)
\(B=1000-3.127\)
\(B=1000-381\)
\(B=619\)
Vậy B = 619
12000 - ( 1500 . 2 + 1800 . 3 + 1800 . 2 : 3 )
= 12000 - ( 3000 + 5400 + 3600 : 3 )
= 12000 - ( 3000 + 5400 + 1200 )
= 12000 - 9600
= 2400
12 000 - (1500 . 2 + 1800 . 3 + 1800 . 2 : 3)
=12 000 - (3000 + 5400 + 3600 : 3)
= 12 000 - (3000 + 5400 + 1200)
= 12 000 - 9600 = 2400
A) 400 + { 106 - [ 23 + ( 4.23 - 6.5 )]}
= 400 + { 106 - [ 8 + ( 4.8 - 30 )]}
= 400 + { 106 - [ 8 + ( 32 - 30 )]}
= 400 + { 106 - [ 8 + 2 ]}
= 400 + { 106 - 10 }
= 400 + 96
= 496
B) 800 : { 111 - [ 32 + ( 23 .5 - 19.2 )]}
= 800 : { 111 - [ 9 + ( 8.5 - 38 )]}
= 800 : { 111 - [ 9 + ( 40 - 38 )]}
= 800 : { 111 - [ 9 + 2 ]
= 800 : { 111 - 11 }
= 800 : 100
= 8
\(A,400+\left\{106-\left\{2^3+\left(4.2^3-6.5\right)\right\}\right\}\)
\(A,=400+\left\{106-\left\{8+\left(4.8-6.5\right)\right\}\right\}\)
\(A,=400+\left\{106-\left\{8+\left(32-30\right)\right\}\right\}\)
\(A,=400+\left\{106-\left(8+2\right)\right\}\)
\(A,=400+\left(106-10\right)\)
\(A,=400+96\)
\(A,=496\)
\(B,800:\left\{111-\left\{3^2+\left(2^3.5-19.2.\right)\right\}\right\}\)
\(B,=800:\left\{111-\left\{9+\left(8.5-19.2\right)\right\}\right\}\)
\(B,=800:\left\{111-\left\{9+\left(40-38\right)\right\}\right\}\)
\(B,=800:\left\{111-\left(9+2\right)\right\}\)
\(B,=800:\left(111-11\right)\)
\(B,=800:100\)
\(B,=8\)