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![](https://rs.olm.vn/images/avt/0.png?1311)
c) 37 . 43
= (40 - 3) . ( 40+3)
= 40^2 - 3^2
= 1600 - 0
= 1591
BÀI 3: viết biểu thức sau dưới dạng tổng, hiệu 2 bình phương.
4 x^2 - 12x - y^2 + 2y + 1
= (2x)^2 -12x +9-y^2 +2y +1
= (2x-3)^2 - (y+1)^2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,x^2-\left(y-2\right)^2=\left(x-y+2\right)\left(x+y-2\right)\)
\(b,\left(2x+5\right)^2-\left(y-3\right)^2=\left(2x+5-y+3\right)\left(2x+5+y-3\right)\)
\(=\left(2x-y+8\right)\left(2x+y+2\right)\)
a) \(x^2-\left(y-2\right)^2\)
\(=\left(x-y+2\right)\left(x+y-2\right)\)
b) \(\left(2x+5\right)^2-\left(y-3\right)^2\)
\(=\left(2x+5-y+3\right)\left(2x+5+y-3\right)\)
\(=\left(2x-y+8\right)\left(2x+y+2\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(-2x+3y+3\right)\left(-2x-3y+3\right)\)
\(=\left(3-2x\right)^2-\left(3y\right)^2\)
b) \(\left(-2x-y+z\right)\left(-2x+y-z\right)\)
\(=\left(-2x\right)^2-\left(y-z\right)^2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a . \(\left(x+y+4\right)\left(x+y-4\right)=\left(x+y\right)^2-4^2\)
b . \(\left(x-y+6\right)\left(x+y-6\right)=x^2-\left(y-6\right)^2\)
c . \(\left(y+2z-3\right)\left(y-2z-3\right)=\left(y-3\right)^2-\left(2z\right)^2\)
d . \(\left(x+2y+3z\right)\left(2y+3z-x\right)=\left(2y+3z\right)^2-x^2\)
\(\text{a,(x-y+6).(x+y-6)}\)
\(=x^2-\left(y-6\right)^2\)